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3241004551 [841]
2 years ago
11

Help me on number problem 9 please

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
3 0
<h2>Answer:</h2>

<u>You can write it as |0 - x| < 6</u>


<h2>Step-by-step explanation:</h2>

Suppose we have a number line and you are moving towards left side so we get negative numbers. The same logic applies here. You are moving to left side from 0 for 4 steps. So you can write it as

|0 - x| < 6 where x is your desired number

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Alex73 [517]
Find a common denominator between the two (this case it would be 18) and bring the fractions up, so 10/9 would be 20/18, and 3/2 would be 27/18. Then, multiply across, and simplify to lowest terms.
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Alekssandra [29.7K]

Answer:Ikr thats the down fall of this i dont think u can sadly

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PLEASE HELPPPP MEEEEEE!!!!
wlad13 [49]
Answer:

It’s B

Step-by-step explanation:


8 0
2 years ago
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\&#10;x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
PLZ HELP WILL MAKR BRAINLIEST
lions [1.4K]

Answer:

It will be 0.2

Step-by-step explanation:

Hope this Helped

5 0
3 years ago
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