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dimulka [17.4K]
3 years ago
13

Christian is rewriting an expression of the form y = ax2 + bx + c in the form y = a(x – h)2 + k. Which of the following must be

true?
h and k cannot both equal zero
k and c have the same value
the value of a remains the same
h is equal to one half –b
Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

the value of a remains the same

Step-by-step explanation:

just took the Transformations of Quadratic Functions quiz on 3dgenuity !

notsponge [240]3 years ago
3 0
"h and k cannot both equal zero" -- yes, it can. if the vertex of a parabola is at (0, 0), there's nothing incorrect/invalid about that!!

"k and c have the same value" -- k and c do not have the same value. "k" is the y-value of the vertex and c is the constant in your quadratic equation, and the constant is not necessarily the y-value.

"the value of a remains the same" -- this is true. the a's in your equations are the same values, because the a-value is the coefficient of the x-variable in both equations. y = a(x - h)^2 and y = ax^2 -- both of these have a applying to your x-variables.

"h is equal to one half -b" -- this isn't true. the formula for calculating the x value of the vertex (h is the x-value of the vertex) is h = (-b/2a). -b/2a is not the same as one half -b because this answer choice doesn't involve the a-value.
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12/k = 18/42 what is k
Maslowich

Answer:

k = 28

Step-by-step explanation:

12/k = 18/42

Cross multiply.

18k = 12 * 42

18k = 504

Divide both sides by 18.

k = 28

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what is the exact value of cos(c+d), given sin c=24/25 for c in quadrant 2 and cos d=-3/4 for d in quadrant 3
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1 3/100

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Which is the correct way to evaluate the expression 48−(29−17)?
Blababa [14]

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Step-by-step explanation:

7 0
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Read 2 more answers
Please help!! and please show the work and the answer!!
kumpel [21]

Company 1: (24 + 26 + 28 + 23 + 21) / 5 (this is how many numbers added together) = 24.4

Company 2: (6 + 32 + 9 + 31 + 21) / 5 = 19.8

Company 3 (15 + 15 + 15 + 15 + 15) / 5 = 15

Company 4: (13 + 10 + 45 + 12 + 15) / 5 = 19

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5 0
3 years ago
1. A rancher wants to build a rectangular pen, using one side of her barn for one side of the pen, and using 200m of fencing for
bezimeni [28]

Answer:

100m by 50m.

Step-by-step explanation:

Let the dimension of the rectangular pen be x and y

Area, A(x,y)=xy

Let the side opposite her barn = x

Since she wants to fence only three side

Perimeter = x+2y

Length of Fencing Available = 200m

Therefore: x+2y=200 \implies x=200-2y

We want to maximize the area of the pen, A(x,y).

Substituting x=200-2y into A(x,y)=xy

A(y)=y(200-2y)\\A(y)=200y-2y^2

To maximize A(y), we find its derivative and solve for the critical points.

A'(y)=200-4y\\$Setting $A'(y)=0\\200-4y=0\\200=4y\\y=50

To ensure that this is a maximum, we use the second derivative test.

A''(y)=-4

This is negative and thus, y=50 is a maximum point.

Recall:

x=200-2y

x=200-2(50)

x=200-100

x=100m

Therefore, the dimensions of the pen that has the largest area are 100m by 50m.

4 0
3 years ago
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