The length of a rectangle is 4 more than twice the width. If the perimeter of the rectangle is 104 centimeters, what are the len
2 answers:
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Answer:
A.
B. Perimeter = 190.6 yd
Step-by-step explanation:
A. Distance between P(10, 50) and R(80, 10):
(nearest tenth)
B. Distance around the park = Perimeter = PR + PQ + QR
PR = 80.6 yd
PQ = |50 - 10| = 40 yd
QR = |80 - 10| = 70 yd
Perimeter = 80.6 + 40 + 70
Perimeter = 190.6 yd
I am assuming you mean 3.0 *10^8 and 1.5 * 10^11.
time = distance/speed right. So,
t = 500 s
time = distance/speed right. So,
t = 500 s