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Tasya [4]
3 years ago
5

you have a bag of marbles. 5 marbles are blue, 4 marbles are red, and 2 marbles are yellow. What is the probability that you pul

l a red marble and then a yellow marble, when the first marble is not replaced before pulling the second
Mathematics
1 answer:
viktelen [127]3 years ago
3 0

Answer:

1. 4/11 2. 2/10 or 1/5

Step-by-step explanation:

The first thing you need to do is find the total number of marble and then break it into their probabilities. 4+2+5= 11

Red: 4/11, Yellow: 2/11 and Blue: 5/11

So for 1. you just need the probability of pulling a red marble with we already figured out, 4/11.

For the second part you're looking for the probability of pulling a yellow marble after a red was pulled and not replaced. When we take one out and don't replace it the only thing that changes is the total and the number for that color so, the probabilities change to: Red: 3/10, Yellow: 2/10 and Blue: 5/10.

So now you have the probability of pulling a yellow if a red was pulled first without being replaced.

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If one root is the square of the other in the equation 8+mx+27x²=0,find the value of m​
aleksklad [387]

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The value of m is -30.

Step-by-step explanation:

Let 27\cdot x^{2}+m\cdot x +8 = 0, we notice that expression is a second order polynomials. We can rearrange the polynomial and use factorization to calculate all roots:

x^{2}+\frac{m}{27}\cdot x + \frac{8}{27} = 0 (1)

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From (3) we find the least root:

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3 0
3 years ago
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