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4 years ago

Why is an alkali metal element like sodium (Na) so reactive?

1 answer:

3 0

Alkali metals are known for being some of the most reactive metals. This is due in part to their larger atomic radii and low ionization energies. They tend to donate their electrons in reactions and often have an oxidation state of +1. These metals are characterized as being extre

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Hamid made this table to organize his notes on the properties of acids and bases.

Molodets [167]

Answer : The property in the wrong column is, base form hydrogen gas with metals

Explanation :

Acid : It is a substance that has ability of donating a proton or hydrogen ion, $H^+$ .

The properties of an acid are :

Acids are sour in taste.
It conduct electricity.
The texture of an acid solution is sticky.
It react with carbonates to give salt.
It changes the color of the litmus paper to red.
It react with a metal to give compound and hydrogen gas.

Base : It is a substance that has ability of donating hydroxide ion, $OH^-$ .

The properties of an base are :

Base are bitter in taste.
It conduct electricity.
The texture of an base solution is slippery.
It changes the color of the litmus paper to blue.
It does not react with a metal.

Hence, from the above information, we conclude that the property in the wrong column is, base form hydrogen gas with metals .

8 0

3 years ago

Read 2 more answers

Two waves were analyzed with some high-tech instrumentation. The first wave was found to have a wavelength of 3 x 10 m and the s

a_sh-v [17]

Explanation:

The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m

We need to find which wave have a higher frequency.

The relation between frequency and wavelength is given by :

$c=f\lambda$

Let f₁ and f₂ be the frequency of wave 1 and wave 2.

$f_1=\dfrac{c}{\lambda_1}\\\\f_1=\dfrac{3\times 10^8}{3\times 10^5}\\\\=1000\ Hz$

And

$f_2=\dfrac{c}{\lambda_2}\\\\f_2=\dfrac{3\times 10^8}{3\times 10^4}\\\\=10000\ Hz$

Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.

8 0

3 years ago

Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) => CH 3OH(l) Using the following information: C(graphite) +

Alika [10]

Answer:

$\Delta H$ for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

$C(graphite)+O_{2}(g)\rightarrow CO_{2}(g)$ $\Delta H_{1}= -393.5 kJ$

$2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)$ $\Delta H_{2}= (2\times -285.8)kJ$

$CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)$ $\Delta H_{3}= 726.4 kJ$

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$C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)$

$\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ$

4 0

4 years ago

Carbon is one of the most common elements found in living things

zzz [600]

Answer:

Major Elements

The six most common elements inliving things are carbon, hydrogen, oxygen, nitrogen, phosphorus, and sulfur. Atoms of these elementscombine and form thousands of large molecules. These large molecules make up the structures of cells and carry out many processes essential to life.

4 0

3 years ago

The population of the Earth at the end of 2018 was approximately 7.7 × 10 9 people. Which of the following is the correct way of

stepladder [879]

Answer:

7700000000

Explanation:

so 7.7 x 10 to the power of 9 is in standard form

to put it into a number you just need to times it by 1000000000

however your answer will only have 8 zeros because of the decimal point

5 0

3 years ago