In a covalent bond one atom can attract the shared electrons more strongly than the other atom can. Water or H2O has a covalent bond whose Oxygen atoms attract more electrons that its Hydrogen atom. Since electrons have a negative charge, the Oxygen atom has a partial negative charge and the Hydrogen atom has a partial positive charge. These partial charges are what make water a polar molecule.marrit <span>· 2 years ago</span>
Answer:
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Explanation:
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In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

Then, we accommodate the waters to obtain:
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Explanation:
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Answer:
4- radioactive isotopes
Explanation:
I don't remember exactly but this question was on the regents
Answer: 94.07%
Explanation:
Percentage yield can be calculated by the formula
%yield = Experimental yield/Theoretical yield x100
Experimental yield = 7.93g
Theoretical yield = 8.43
%yield = Experimental yield/Theoretical yield x100
%yield = 7.93/8.43 x 100 = 94.07%