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spayn [35]
3 years ago
8

. Which piece of safety equipment is least likely to be at Jerome's lab station? A. Goggles B. A fire extinguisherC. Heat-proof

gloves D. A lab coat
Chemistry
1 answer:
charle [14.2K]3 years ago
5 0
D a lab coat
hsjjdjjfdh

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Help with this question I don’t get it I will give out 30 points!!!
Paladinen [302]

Answer: The second choice

Explanation: The question is most likely asking what the arrow's pointing at, and it's right at the meeting point for lines x and y. Lines x and y would be the common ancestors of the point the arrow is showing since they're above the point and meet up to the point.

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Worth 13 points plzzz helpp
serious [3.7K]

The fourth one is correct yw

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If you had excess aluminum, how many moles of aluminum chloride could be produced from 21.0 g of chlorine gas, cl2?
AleksandrR [38]
When aluminum metal is made to contact with chlorine gas (Cl₂), a highly exothermic reaction proceeds. This produces aluminum chloride (AlCl₃) powder. The balanced chemical equation for this reaction is shown below:

2Al(s) + 3Cl₂(g) → 2AlCl₃(s)

Since it was stated that aluminum is in excess, this means that the amount of AlCl₃ produced will only depend on the amount of Cl₂ gas available. The molar mass of Cl₂ is 70.906 g/mol. Using stoichiometry, we have the following equation:

(21.0 g Cl₂/ 70.906 g/mol Cl₂) x 2 mol AlCl₃/ 2 mol Cl₂ = 0.1974 mol AlCl₃

Thus, we have determined that 0.1974 <span>moles of aluminum chloride can be produced from 21.0 g of chlorine gas. </span>
3 0
3 years ago
1. What did Henri Becquerel discover about<br> radiation emitted from uranium salts?
Dmitriy789 [7]

Explanation:

When Henri Becquerel investigated the newly discovered X-rays in 1896, it led to studies of how uranium salts are affected by light. By accident, he discovered that uranium salts spontaneously emit a penetrating radiation that can be registered on a photographic plate.

6 0
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As a pilot is flying in level flight at 9,500 ft, the altimeter in the instrument panel is set to a pressure of 29.48 mm of Hg.
bearhunter [10]

Answer:

from the ideal gas law, P2 /P1 = T2 /T1 for the same volume and quantity of gas. P2 = (758 mmHg) (45 +273 K) / (15 +273K) = 837 mmHg.

Explanation:

4 0
2 years ago
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