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3 years ago

How do you solve 2x^2+4x=3+3x^2?

Mathematics

1 answer:

allochka39001 [22]3 years ago

5 0

Answer:

5x^2+4x=3

Step-by-step explanation:

You add the like terms: 3x^2 and 2x^2, you get 5x^2. You can't do anything else because there are no more terms that are alike.

So the answer would be 5x^+4x=3

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What is 16+x=12 and -3x=15

horrorfan [7]

-4 and -5
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3 years ago

Read 2 more answers

−7x−50≤−1 AND−6x+70>−2

fgiga [73]

Answer:

$-7\geq x$ and $[-7,12)$ in interval notation.

Step-by-step explanation:

We have been given a compound inequality $-7x-50\leq -1\text{ and }-6x+70>-2$ . We are supposed to find the solution of our given inequality.

First of all, we will solve both inequalities separately, then we will combine both solution merging overlapping intervals.

$-7x-50\leq -1$

$-7x-50+50\leq -1+50$

$-7x\leq 49$

Dividing by negative number, flip the inequality sign:

$\frac{-7x}{-7}\geq \frac{49}{-7}$

$x\geq -7$

$-6x+70>-2$

$-6x+70-70>-2-70$

$-6x>-72$

Dividing by negative number, flip the inequality sign:

$\frac{-6x}{-6}$

$x$

Upon merging both intervals, we will get:

$-7\geq x$

Therefore, the solution for our given inequality would be $-7\geq x$ and $[-7,12)$ in interval notation.

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Brilliant_brown [7]

Answer:

The graph is included in the attached pictures

Step-by-step explanation:

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