Solve for x:
x + (x + 2) + (x + 4) = 27
3x + 6 = 27
3x = 27 - 6
3x = 21
3x / 3 = 21 / 3
x = 7
The integers:
x + (x + 2) + (x + 4) = 27
7 + (7 + 2) + (7 + 4) = 27
7 + 9 + 11 = 27
27 = 27
The integers are 7, 9 , 11
Answer:
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Step-by-step explanation:
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
Answer:
5 units. Since they have the same y coordinate the x coordinate determines the distance from each other. In the case 9-4=5.
Answer:
x=5
Step-by-step explanation:
Other than using the plain special aspect of a 45-45-90 triangle where the legs are x, x, and x√2, you can solve for this.
Since the two legs have equal length, they are both x. Using the pythagorean theorem:
(x^2)+(x^2)=50 (Because 5 squared is 25 and √2 squared is 2, multiplying them gives you 50).
You can add (x^2) and (x^2) because they are the same terms (x squared).
Simplifying like so gives you:
2x^2=50
Dividing by two on both sides:
x^2=25
Taking the square root of both sides:
x=5
