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3 years ago

What is the area of a rectangle that has a perimeter of 87.20?

Mathematics

1 answer:

harkovskaia [24]3 years ago

5 0

The answer is 43.6 your welcome 87.20 divided by two is 43.6.

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A frozen pizza cost $3.00 in 2000. In 2015 it cost $2.50

user100 [1]

There’s a 50 cents difference woahhhh

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2 years ago

Read 2 more answers

Megan has a piece of fabric which is a right triangular shape. The length of leg 1 is 4 m. The length of the other leg is twice

Bess [88]

Answer:

8.94 m

Step-by-step explanation:

Use the Pythagorean Theorum - $a^2 + b^2 = c^2$ . Use leg 1 as a, leg 2 as b, and the third side as c.

We know leg 1 is 4, and that leg 2 is twice as long as leg 1...

$(4)^2 + (4*2)^2 = c^2$

Now, we use the Order of Operations to find $c^2$ ...

$4^2+8^2=c^2\\16+64=c^2\\80=c^2$

Now, we find the square root of $c^2$ to find c...

$\sqrt{80} =8.94$

So, the length of the third side is 8.94 m.

8 0

2 years ago

How many solutions does the system of equations have?

34kurt

Answer:

No i will not

Step-by-step explanation:

fsdfsdfsdfsdfsdfsdfsdfasadfsdfasdfsdafdfgrdfgdfgrgdf

3 0

3 years ago

I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help

VMariaS [17]

Answer: a) 8.779 years

b) 8.664 years

Step-by-step explanation:

$A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}$

A: accumulated amount (balance)
P: principal amount (original/initial investment)
r: interest rate (convert to a decimal)
n: number of times compounded per year
t: number of years

Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

$1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}$

$A=Pe^{rt}$

$1800=900e^{0.08t}\\\\\\2=e^{0.08t}\\\\\\ln\ 2=0.08t\\\\\\\dfrac{ln\ 2}{0.08}=t\\\\\\\large\boxed{8.664=t}$

4 0

2 years ago

Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$

The minimum initial velocity needed for the ball to clear the fence is $125.4\ \text{m/s}$

5 0

2 years ago