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iren2701 [21]
3 years ago
10

HELP PLEASE???? ???????

Mathematics
2 answers:
lord [1]3 years ago
7 0
For every hour she works, her earnings go up by $10.
SOVA2 [1]3 years ago
5 0
We first need to see where the line intersects at a certain point.  The easiest way to do this is when X = 1, which in this case there is a 1 mark on the x axis.  From there we go up and see where the line intersects with it and the Y axis.  In this case at 1 hour she earns $10.  Since the line is straight, it is a constant slope and she is earning the same amount every hour.  From this we can conclude that the  answer is D, for every hour her earnings go up by $10
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Answer:

The radius is 5

Step-by-step explanation:

The equation for Area of a sphere is

4pi*r^2

Since you have the area and not the radius you do the opposite of the equation so instead of multiplying you divide

100/4 = 25

Then find the square root of 25, which is 5

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Hope This Helps!!! :}

8 0
3 years ago
04.03 HC)
faust18 [17]

Part A:

To find the average rate of change, let us first write out the equation to find it.

Δy/Δx = average rate of change.  

Finding average rate of change for Section A

Δy = f(1) - f(0) = 2(3)^1 - 2(3)^0 = 6 - 1 = 5

Δx = 1- 0 = 1

Plug the numbers in: Δy/Δx = 5/1 = 5

Therefore, the average rate of change for Section A is 5.  

Finding average rate of change for Section B

Δy = f(3) - f(2) = 2(3)^3 - 2(3)^2 = 2(27) - 2(9) = 54 - 18 = 36

Δx = 3 - 2 = 1

Plug the numbers in: Δy/Δx = 36/1 = 36

Therefore, the average rate of change for Section B is 36.  

Part B:

(a) How many times greater is the average rate of change of Section B than Section A?

If Section B is on the interval [2,3] and Section A is on the interval [0,1].  

For the function f(x) = 2(3)^x, the average rate of change of Section B is 7.2 times greater than the average rate of change of Section A.  

(b) Explain why one rate of change is greater than the other.  

Since f(x) = 2(3)^x is an exponential function the y values do not increase linearly, instead increase exponentially. In an interval with smaller x values the rate of change is lower than an interval with larger x values.

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Step-by-step explanation:

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