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VMariaS [17]
2 years ago
5

Calculate the surface area of the aquarium, without the top.24 cm80 cm16 cm​

Mathematics
1 answer:
larisa86 [58]2 years ago
3 0
Well you never sent a picture but the most logical answer is 80 cm
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How do i find the measure of an interior angle of a regular polygon with 12 sides
Blizzard [7]
What grade are you?
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5 0
3 years ago
This is urgent, please answer!
Alex17521 [72]

1/2 = 0.5

12 & 1/2 = 12 + 1/2 = 12 + 0.5 = 12.5

4 & 1/2 = 4 + 1/2 = 4 + 0.5 = 4.5

Refer to the diagram below. Note how I divided the figure into two rectangles.

The larger red rectangle is 12.5 feet by 10 feet. It has area 12.5*10 = 125 square feet.

The smaller blue rectangle has dimensions 4.5 feet by 5 feet (the 5 is from 15-10 = 5), so it has area 4.5*5 = 22.5 square feet

Now add up those individual areas to get the total area

125+22.5 = 147.5

Then convert that to a mixed number

147.5 = 147 + 0.5 = 147 + 1/2 = 147 & 1/2

<h3>The correct area is 147 & 1/2 feet</h3>

8 0
3 years ago
Which graph represents a function?
salantis [7]

Answer:

It is the answer closest to the right. The one with a straight line.

Step-by-step explanation:

Because it is a function if there is only one dot per line vertically. The others have either 2 or more dots per line vertically.

7 0
3 years ago
7 1/3 + 5 5/6 sum up as a fraction please 100 points
beks73 [17]

Answer:

The answer is 13 1/6

Step-by-step explanation:

The answer is 18 because 7 1/3 turns into 7 2/6 and 7 * 6 is 42 and 42 plus 2 is 44. Next You turn 5 5/6 into a improper fraction which turns into 35/6 and 35 plus 44 is 79/6 and 79/6 simplified is 13 1/6

3 0
2 years ago
The goal of a nutritional study was to compare the caloric intake of adolescents living in rural areas of the US with the calori
stiks02 [169]

Answer:

To give more clarity to the question, lets examine the attached back-to-back stem plot.

A)

Having examined the stem plot, we can using quick calculations, summarize that:

The mean (40.45 cal/kg) and median (41 cal/kg) daily caloric intake of ninth-grade students in the rural school is higher than the corresponding measures of center, mean (32.6 cal/kg) and median (32 cal/kg), for ninth-graders in the urban school.

The median and the mean for the students in the 9th grade in the urban school is lower than that of those of their contemporaries in the rural school. The respective medians and means are stated below:

Urban 9th Grade Students

Median = 32 cal/kg

Mean = 36 cal/kg

Rural 9th Grade Students

Median = 41 cal/kg

Mean = 41 cal/kg

Please note that all figures above have been approximated to the nearest whole number.

B)

It is unreasonable to generalize the findings of this study to all rural and urban 9th-grade students in the United States because the sample is too small compared to the target population size.

To allow for generalization, they would have to collect and analyze more samples say from every state within America.

Cheers!

5 0
3 years ago
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