Answer:
x^2 + 2x - 8
Step-by-step explanation:
h(x) + k(x) = (2x^2 + 5x - 12) + (-x^2 - 3x + 4)
Add Like Terms
(2x^2 + 5x - 12) + (-x^2 - 3x + 4)
2x^2 - x^2 = x^2
(2x^2 + 5x - 12) + (-x^2 - 3x + 4)
5x - 3x = 2x
(2x^2 + 5x - 12) + (-x^2 - 3x + 4)
-12 + 4 = -8
x^2 + 2x - 8
Answer:
Step-by-step explanation:
Answer:
C. 24 + 32
Step-by-step explanation:
Step 1 - Distribute
4 • 6 = 24
4 • 8 = 32
24 + 32
Answer:
Yes, Rolle's theorem can be applied
There is only one value of c such that f'(c) = 0, and this is c = 1.5 (or 3/2 in fraction form)
Step-by-step explanation:
Yes, Rolle's theorem can be applied on this function because the function is continuous in the closed interval (it is a polynomial function) and differentiable in the open interval, and f(a) = f(b) given that:

Then there must be a c in the open interval for which f'(c) =0
In order to find "c", we derive the function and evaluate it at "c", making the derivative equal zero, to solve for c:

There is a unique answer for c, and that is c = 1.5