You say that there is uniform acceleration so:
vf-vi=at (final velocity minus initial velocity is equal to acceleration times time)
We know vf, vi, and t so we can solve for acceleration:
24-12=a10
12=10a
a=1.2
That is the acceleration, we will need to integrate with respect to time twice...
v=⌠a dt
v=at+vi , we know a=1.2m/s^2 and vi=12m/s
v=1.2t+12,
x=⌠1.2t+12 dt
x=1.2t^2/2+12t+xo, we can just let xo=0 for this problem...
x(t)=0.6t^2+12t
Now we know that this acceleration lasts for 10 seconds so the distance traveled in that time is:
x(10)=0.6(10^2)+12(10)
x(10)=60+120
x(10)=180 meters
I believe that the snail would be 43 5/12 inches away from the bottom after 20 minutes.
Step-by-step explanation:
400 meters is standard lap distance for a race track. 2 x 50 meters is lap distance in International pools. A lap of 440 yards is 1/4 mile. So 4 laps/mile.
Answer:
Third option: 
and 
Step-by-step explanation:
Given:
For a modulus function, if 
, then,
Here, 
, 
∴ 
Therefore, the third option is the correct answer as the graph has 
values as -2 and 2
