(x + 5)(y + 10)
x(y + 10) + 5(y + 10)
x(y) + x(10) + 5(y) + 5(10)
xy + 10x + 5y + 50
Answer:
1 is 1/2 5 is 2 1/2 and 7 would be 3 1/2
Step-by-step explanation:
Answer:
-96.875
Step-by-step explanation:
302 times 16 because he passed 302 yards for every game 4832
Answer:
The answer to this question would be B:
Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.
Hope this reached you well :)
Step-by-step explanation:
20 = weight of the weight plates
x = amount of weight plates.
5 = weight of the barbell
f(x) = 20(0) + 5 = 5
f(x) = 20(1) + 5 = 25
f(x) = 20(2) + 5 = 45
f(x) = 20(3) + 5 = 65
f(x) = 20(4) + 5 = 85
