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3 years ago

Answer it with proof please, so I know how you got it.

Mathematics

2 answers:

Alex Ar [27]3 years ago

4 0

I think it's 79.50 square units. there three triangles in the quadrilateral shape above with the areas given so add the areas together to get the answer

Lesechka [4]3 years ago

3 0

Answer:

79.5 units²

Step-by-step explanation:

The figure ABCDE is composed of the 3 triangles, hence

area of ABCDE = area ΔABC + area ΔACD + area ΔAED

= 23.85 + 29.4 + 26.25 = 79.5 units²

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Hi, I'm often really slow at learning math and my condition makes it harder, can someone help me?

NARA [144]

The answer: 0, 4/5 and 5

Explanation: first, we factor out 2x and get: 2x(5x^2-29x+20)=0

In order for this equation to be equal to zero, either 2x must equal to zero or (5x^2-29x+20) must equal to zero

Having said that, if:
2x = 0
X=0

If:
(5x^2-29x+20) = 0
X=4/6, x=5

7 0

2 years ago

A restaurant operator in Accra has found out that during the lockdown,if she sells a plate of her food for Ghc 20 each,she can s

ella [17]

The demand equation illustrates the price of an item and how it relates to the demand of the item.

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85

From the question, we have:

$Plates = 300$

$Price = 20$

The number of plates (x) decreases by 10, while the price (y) increases by 5. The table of value is:

$\begin{array}{cccccc}x & {300} & {290} & {280} & {270} & {260} \ \\ y & {20} & {25} & {30} & {35} & {40} \ \end{array}$

The slope (m) is calculated using:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

So, we have:

$m = \frac{25-20}{290-300}$

$m = \frac{5}{-10}$

$m = -\frac{1}{2}$

The equation of the demand is as follows:

The initial number of plates (300) decreases by 10 is represented as: (300 - 10x).

Similarly, the initial price (20) increases by 5 is represented as: (20 + 5x).

So, the demand equation is:

$R(x) = (300 - 10x) \times (20 + 5x)$

Open the brackets to calculate the maximum revenue

$R(x) =6000 + 1500x - 200x - 50x^2$

$R(x) =6000 + 1300x - 50x^2$

Equate to 0

$6000 + 1300x - 50x^2 =0$

Differentiate with respect to x

$1300 - 100x =0$

Collect like terms

$100x =1300$

Divide by 100

$x =13$

So, the price at maximum revenue is:

$Price= 20 + 5x$

$Price= 20 + 5 * 13$

$Price= 85$

In conclusion:

The slope of the demand function is -1/2
The equation of the demand function is: $R(x) = (300 - 10x) \times (20 + 5x)$
The price that maximizes her revenue is: Ghc 85

Read more about demand equations at:

brainly.com/question/21586143

3 0

3 years ago

Dean invests $500 for 10 years at a rate of 1.7% per year simple interest. Calculate the total interest earned during the 10 yea

Ann [662]

Answer: $85

Explanation:

4 0

3 years ago

A student conducts several random surveys to find out the most preferred lunch option. Each survey was of 60 students. No studen

stira [4]

Answer:

is the answer

I think soo

5 0

3 years ago

3yd 4yd what is the length of the hypotenuse

hjlf

Answer:

5 yd

Step-by-step explanation:

Use Pythagorean theorem,

Hypotenuse² = base² + altitude²

= 3² + 4²

= 9 + 16

= 25

Hypotenuse = √25 = √5*5 = 5 yd

6 0

3 years ago