<em><u>Question:</u></em>
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
<em><u>Answer:</u></em>
The vertical asymptotes are x = 2 or x = -1
<em><u>Solution:</u></em>
Given that,
For vertical asymptotes, set the denominator to zero and then solve the quadratic equation
Thus the vertical asymptotes are x = - 1 and x = 2
M<1 = 360 / 3 = 120
m<2 = 120/2 = 60
m<3 = 180 - 90 - 60
m<3 = 30
answer
30 (third choice)
Answer:
Step-by-step explanation:
You have to divide -5 from each side so -5/-5x which would be x and divide -5 by 40 which is -8 so x is greater than or equal to -8
Answer:
x = 19°
Step-by-step explanation:
we can see from observation that 22° and (3x+11)° are complementary. I.e they add up to 90°
hence
22 + (3x+11) = 90
22 + 3x+11 = 90
33 + 3x = 90 (divide both sides by 3)
11 + x = 30 (subtract 11 from both sides)
x = 30 - 11
x = 19°
3 bags = 16 m
1 bag = 5/1/3 m
5 bags = 26 m 40 seconds
i am a mathematics teacher. if anything to ask please pm me
