Since the intersection is - by definition - common to both sets, we can work out the number of people that use only the fitness suite or the swimming pool.
We know that 57 people use the fitness suite, but 36 of those are already counted in the intersection. So, 57-36=21 people use only the fitness suite.
The same goes for the swimming pool: 49-36=13 people use only the swimming pool.
So, we have:
- 21 people using fitness suite only
- 13 people using swimmng pool only
- 36 people using both
This sums to 21+13+36=70 people. We deduce that 30 people don't use any of the features.
The answer A because I did the math and y is -20 and x is -12
Answer:
D: 132 ft
Step-by-step explanation:
C= π2r
So, take pi and multiply that by two..
π2= 6.28
Now, take your radius and multiply it by 6.28.
21 x 6.28= 131.88
Round it two the nearest whole number, which is 132!
Hope this helps!
Answer:
14400 blinks per day
Step-by-step explanation:
We need to convert minutes to days
60 minutes = 1 hour
24 hours = 1 day
The units will cancel leaving blinks per day.
150 blinks 60 minutes 24 hour 216000
---------------- * ---------------------- * ------------ = --------------- blinks/day
15 minutes 1 hour 1 day 15
14400 blinks per day
First one,
12q^2+34q-28
divide whole thing by 2
6q^2+17q-14
use trial and error and get (2x+7)(3x-2)
factored out form is (2)(2x+7)(3x-2)
2.
divide by 3
6h^2+5h-6
trial and error and get (2x+3)(3x-2)
so the factored form is (3)(2x+2)(3x-2)
3. divide by 2
6p^2-11x-10
use trial and error and get (2x-5)(3x+2)
the factored out form is (2)(2x-5)(3x+2)
4.divide by 4
2z^2+5z-12
use trial and error and get (x+4)(2x-3)
the factored form is (4)(x+4)(2x-3)
to factor the basic thing is
ax^2+bx+c
b=x+y
ac=xy
solve for x and y
so exg 2z^2+5z-12
a=2
b=5
c=-12
2 times -12=-24
then factctor -24 and find factors that add up to 5
-1, 24
-2, 12
-3, 8
-4,6
now add
-1+24=23
-2+12=10
-3+8=5 check
-4+6=2
the numbers are -3 and 8
split it into such
2z^2+8z-3z-12
group (2z^2+8z)+(-3z-12)
undistribute using distributive property
ab+ac=a(b+c)
(2z)(z+4)+(-3)(z+4)
now reverse distribute again
((2z)+(-3))(z+4)
(2z-3)(z+4)