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3 years ago

8

2ln(x+4)1/-2ln(2x+5 write as a single logarithm

1 answer:

kifflom [539]3 years ago

6 0

Well from combining I got ㏑(x²+10x+21)/-2

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Let r3 have the euclidean inner product. let u = (-1, 1, 1) and v = (-7, 6, 15). if ||ku + v||= 7, what is k? give the exact ans

amm1812

Ma $k\mathbf u+\mathbf v=k(-1,1,1)+(-7,6,15)=(-k-7,k+6,k+15)$

Recall that for a vector $\mathbf x\in\mathbb R^n$ , we have $\|\mathbf x\|=\sqrt{\mathbf x\cdot\mathbf x}$ . So we have

$\|k\mathbf u+\mathbf v\|=\sqrt{(k\mathbf u+\mathbf v)(k\mathbf u+\mathbf v)}=7$
$\implies k^2\mathbf u\cdot\mathbf u+2k\mathbf u\cdot\mathbf v+\mathbf v\cdot\mathbf v=49$
$\implies3k^2+56k+261=0$
$\implies k=-9,-\dfrac{29}3$

3 0

2 years ago

Which recursive formula represents the geometric sequence?<br> 25, 20, 16,

slavikrds [6]

Answer:

Step-by-step explanation:

$a_n=\frac{4}{5}(a_{n-1})$

6 0

3 years ago

It has been estimated that 72.7% of alcoholics need professional help to stop drinking. What is the probability that a random al

Svetradugi [14.3K]

The probability that a random alcoholic can kick the habit without professional help is 0.273 .

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It has a range of 0 to 1 , where 0 indicates uncertainty and 1 indicates certainty.

It is given that

The alcoholics that need professional help to stop drinking is 72.7 %

Therefore the probability of this is 72.7 /100 = 0.727

The probability that they will not need professional help is given by

q = 1 - p

q = 1 -0.727

q = 0.273

Therefore the probability that a random alcoholic can kick the habit without professional help is 0.273 .

To know more about Probability

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5 0

1 year ago

Mrs. Heath baked 56 cookies. She put an equal number of cookies into 7 bags. How many cookies did she put in each bag?

katen-ka-za [31]

Answer:

8

Step-by-step explanation:

you have to divide 56 by 7 and you will get 8.

6 0

2 years ago

Read 2 more answers

(2a)(2b) please help

DENIUS [597]

The answer is 2^a+b lol

3 0

3 years ago