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Mariulka [41]
2 years ago
9

At which values of x does the graph of the function F(x) have a vertical asymptote? F(x)=x+2/x^2+2x-24 check all that apply.

Mathematics
1 answer:
GalinKa [24]2 years ago
8 0

Answer: X=4 X=-6

Step-by-step explanation:

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3 years ago
Which statement is true?
Vladimir [108]

Answer:

1 yard = 3 feet

Step-by-step explanation:

1 yard = 3 feet

4 0
3 years ago
If f(x) = 4x²-2 then f(-2) is​
klemol [59]
To find f(-2), substitute (-2) into x of the function f(x) = 4x^2-2
We get, f(-2) = 4(-2)^2 - 2
= (4*4)-2 = 16-2 = 14
Therefore, f(-2)=14.
3 0
2 years ago
Please help due ASAP <br> Please show workings!!
Kazeer [188]

Answer:

FC = 27, QC = 18

Step-by-step explanation:

The centroid Q is \frac{1}{3} the way along CF , therefore, QF is half as long as CQ

Given FQ = 9, then

QC = 2 × 9 = 18

FC = FQ + QC = 9 + 18 = 27

8 0
2 years ago
Find the second derivative y=1/5x^2+1/11x
Amiraneli [1.4K]

\frac{dy}{dx}=\frac{1}{5}.x^{2-1}.2 + \frac{1}{11}.x^{1-1}.1

\frac{dy}{dx}=\frac{2}{5}.x+\frac{1}{11}

\frac{d^2y}{dx^2}=\frac{2}{5}.x^{1-1}.1

\frac{d^2y}{dx^2}=\frac{2}{5}

8 0
3 years ago
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