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Maslowich
3 years ago
13

Find two consecutive odd integers whose product is 323

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0
Use a let statement 
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
        -323  -323
x^2 + 2x -323 = 0

third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19 
x = -17

hope this help

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Answer:

1/12

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X - odd - even - even         2 · 5  · 5 · 4 = 200
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Does anyone know the answer?
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I've attached the solution.

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