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Maslowich
3 years ago
13

Find two consecutive odd integers whose product is 323

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0
Use a let statement 
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
        -323  -323
x^2 + 2x -323 = 0

third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19 
x = -17

hope this help

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\qquad\qquad\huge\underline{{\sf Answer}}♨

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How do I solve this question?
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<u>Step</u> :-

Given  [ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

using algebraic formula (a^m)^n= a^{mn}

now

2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}

now equating 'x' powers, we get

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verification:-

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