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Anna11 [10]
3 years ago
13

Use the domain and range of each of the following relations to determine which is a function.

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0
The answer js A. the first one
Margaret [11]3 years ago
5 0

Answer:

The function is expressed by answer A

Step-by-step explanation:

A function is a mathematical expression in which, for an independent variable , usually called x, we obtain one and only one value after applying the function, usually known as the dependent variable y.

D is not a function as we do not have two corresponding values or coordinate pairs. We only have a list of numbers

In C, B and A we have pairs of coordinate values expressed as (x,y) the independent and dependent variable.

In expression B, we see that the for the value of x=3 in ponts 1 (3.-3) and (3.-9) , the value 3 has two resulting values of y , -3 and -9, so this coordinates do not represent a function.

In option C, occurs something similar in this case with x =9. x=9 has two values in y : y=-6 and y= 2 so these points do not define a function

In A each x value (3.9.0) has a unique avlue of y (-3,-6,-9) so this is a function.

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Answer:

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Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
What is equivlent to 15x-20
Tanzania [10]

Answer:

5(3x - 4)

Step-by-step explanation:

5(3x - 4)

use the distributive property

15x - 20

so its correct

8 0
3 years ago
The given right rectangular prism is composed of small cubes. Find the following is the volume of the prism and the volume of on
valina [46]

Answer:

The big prism= \frac{25}{18} feet squared

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Step-by-step explanation:

The big prism LxWxH

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5 0
3 years ago
Surface Area of Cylinder=2πrh+2πr2
Alex

  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

\qquad C. 288π in²

\qquad D. 256π in² ☑

We are given –

\qquad ⇢Radius of cylinder , r = 8 inches

\qquad⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }

Now, Substitute given values –

\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  =128 \pi + 128\pi

\purple{\bf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 256\pi \: in^2 }

  • Henceforth,Option D is the correct answer.

8 0
2 years ago
the tempature dropped 8 degrees between 6:00 p.m. and midnight. The tempature at midnight was 26 degreesF. Write and solve an eq
sashaice [31]
D=degrees at 6

26-8=d
d=18

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3 years ago
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