The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
Step-by-step explanation:
on the edge of a cliff overlooking the Pacific ocean. You see a sailboat down in the water below you. The angle of depression to the sailboat is 28◦ . A quick tells you that the cliff you’re standing on is 150ft. How far away from the boat are you, in feet, rounded to one decimal place?(30pts)
We solve using the Trigonometric function of TANGENT
tan 28 = 150/x
If the bicyclists is traveling 18 miles every hour and needs to travel a sum of 90 miles, you need to divide 90/18 equaling the total time (in hours) needed to travel 90 miles. Hope this helps
Answer:
-6x - 12
Step-by-step explanation:
-2 ( 3x + 6 )
= -6x - 12
Negative Exponent Rule:
this says that negative exponents in the numerator get moved to the denominator and become positive exponents. Negative exponents in the denominator get moved to the numerator and become positive exponents.
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