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postnew [5]
2 years ago
12

A teacher bought 7 packs of dominoes for a math game. Each pack had 55 dominoes. The teacher already had 118 dominoes to use in

the game.
Mathematics
1 answer:
S_A_V [24]2 years ago
6 0

Answer:

540540 dominoes

Step-by-step explanation:

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Two number cubes are rolled. Each number cube has sides numbered 1 through 6.
olasank [31]
P(odd) or P(multiple of 5)
When we roll 2 number cubes

all possible outcomes of their sum are 2,3,4,5,6,7,8,9,10,11,12.(11 possible outcomes)

Out of those possible outcomes
3,5,7,9,11 are odd (5 outcomes) and ...

5 and 10 are multiples of 5 (2 outcomes)

Now, P(odd) or P(multiple of 5) really means P(odd) + P (multiple of 5) =
(If we had “and” instead of “or” we multiply)
= (5/11) +(2/11)
=7/11
7 0
3 years ago
Read 2 more answers
5 kilograms of coffee are going to be shared equally among 44 people.
liraira [26]

Answer:

A

Step-by-step explanation:

5/44=0.11kg

4 0
1 year ago
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Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
Item 4
Simora [160]

Answer:

270 s

Step-by-step explanation:

4 minutes = 240s

add the other 30s

boom

5 0
2 years ago
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Henri paid $10.75 for a calculator, $4.98 for copier paper, and $3.21 for folders. He paid with a $20 bill and got $1.06 in chan
Amiraneli [1.4K]

Answer:

10.75+4.98+3.21=18.94

20-18.94= 1.06

Step-by-step explanation:

up their

7 0
3 years ago
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