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Sunny_sXe [5.5K]
3 years ago
14

In which area of the brain does mathematical processing occur?

Mathematics
2 answers:
ivolga24 [154]3 years ago
4 0
<span>lIt occurs in the left parietal lobe. 

Happy studying ^-^</span>
Veseljchak [2.6K]3 years ago
3 0
I believe it's in the <span>left parietal lobe. :) </span>
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7/9+7/54 what is the answer
kolbaska11 [484]

Answer:

49/54

Step-by-step explanation:

7/9 + 7/54

42/54 + 7/54

49/54

3 0
3 years ago
In ∆ KLM above, NO // ML and &lt; KNO = &lt; KON. Find m &lt; MNL =
4vir4ik [10]

Answer: In ∆ KLM above, NO // ML and < KNO = < KON. Find m < MNL =

Step-by-step explanation: dUNNO

6 0
2 years ago
Two angles of a triangle measure 45 degrees and 90 degrees. What is the third angle measure?
neonofarm [45]

Answer:

B

Step-by-step explanation:

Angles in a triangle add up to 180

Take 45 + 90 then subtract the answer from 180

6 0
2 years ago
Prove the identity<br> cos(A+B+C)=cosAcosBcosC-cosAsinBsinC-sinAcosBcosC-sinAsinBcosC
blagie [28]
Hello !

cos (a+b) = cos a cos b - sin a sin b
sin (a+b) = sin a cos b + sin b cos a

cos (a+b+c) = cos (a+(b+c))
cos (a+b+c) = cos a cos (b+c) - sin a sin (b+c)
cos (a+b+c) = cos a (cos b cos c - sin b sin c) - sin a (sin b cos c + sin c cos b)
cos (a+b+c)=cos a cos b cos c - cos a sin b sin c - sin a sin b cos c - sin a cos b sin c
4 0
2 years ago
The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the pas
Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is = \frac{(n+1)}{2}.

\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5  position orders

10^{th} \ and \ 11^{th} place an average of observations so, the

Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

Q_1 often falls throughout the ordered BELOW average is = \frac{(n+1)}{2} place.

\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}ordered position

Average 5^{th} \ and \ 6^{th}  location findings

Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5

In  = \frac{(n+1)}{2} the ordered place, Q3 always falls ABOVE the median.

\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th} ordered At median ABOVE 

Consequently Q_3 falls between 5^{th} \ and \ 6^{th} ABOVE the median position

15^{th}\  and \ 16^{th}place average of observations

\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2}  = 502

\to IQR = Q_3 - Q_1= 502-358.5= 143.5  

\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25

4 0
2 years ago
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