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bekas [8.4K]
3 years ago
11

The mean of this set of data (23,13,17,11,11)

Mathematics
1 answer:
Dovator [93]3 years ago
7 0

Answer:

The mean is 15

Step-by-step explanation:

To find the mean, add up all the numbers and divide by the number of numbers

(23+13+17+11+11)/ 5

75 /5

15

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The confidence interval based on the two-sample design is wider because there is considerable variation in mileage between the c
vovikov84 [41]

Answer:

The confidence interval based on the paired design is wider because there is little variation in mileage between the cars.

Step-by-step explanation:

The sample size randomly collected is matched sample and since the confidence interval is based on the paired design is large and wide. There is small variation between the mileage of the two cars indicating the cars have mileage based on the fuel.

5 0
3 years ago
Find the value of x and y<br><br><br>Please help me. Thank you​
STatiana [176]

Answer:

Step-by-step explanation:

let each angle=A

A+A+A=180

3A=180

A=180/3=60°

as the angles are equal so sides are equal.

16+y=46

y=46-16=30

applying sine formula

\frac{30}{sin z} =\frac{46}{sin~80} \\sin~z=\frac{30}{46} \times ~sin~80=\frac{15}{23} \times sin ~80\\z=sin^{-1}( \frac{15}{23} \times sin ~80) \approx~39.96^\circ \approx40^\circ

z+x=60

40+x=60

x=60-40=20°

5 0
3 years ago
In a one-tail test, the p-value is found to be equal to .068. If the test had been two-tail, the p-value would have been
devlian [24]

Answer:

The p-value for two-tailed test is 0.136

Step-by-step explanation:

Given;

one-tail test, p-value = 0.068,

In one-tailed test, we test for the possibility of a relationship in one direction and completely disregard the possibility of a relationship in the other direction.

One-tail test provides possibility of an outcome in one direction, while

two-tail test provides possibility of an outcome in two different directions.

Thus, the p-value for two-tailed test = 2 x 0.068 = 0.136

3 0
3 years ago
If f(x)=2x+1 and g(x)=(x^2)-7, find (f/g)(x).
alexdok [17]

f(x)=2x+1;\ g(x)=x^2-7\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\boxed{\left(\dfrac{f}{g}\right)(x)=\dfrac{2x+1}{x^2-7}}

6 0
3 years ago
Read 2 more answers
Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . .
4vir4ik [10]
10.5, 11, 11.5, 12, 12.5...this is an arithmetic sequence with a common difference of 0.5

an = a1 + (n - 1) * d
n = term to find = 23
a1 = first term = 10.5
d = common difference = 0.5

sub and solve

a(23) = 10.5 + (23 - 1) * 0.5
a(23) = 10.5 + 22 * 0.5
a(23) = 10.5 + 11
a(23) = 21.5 <===
6 0
3 years ago
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