The given expression is:
![\sqrt[5]{64 x^{7} w^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20)
The expression can be simplified as follows:
![\sqrt[5]{64 x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{6} x^{7} w^{5} } \\ \\ = \sqrt[5]{(2)^{5}*2* x^{5}* x^{2} * w^{5} } \\ \\ = \sqrt[5]{ (2^{5} x^{5} w^{5} )*2 x^{2} } \\ \\ = \sqrt[5]{(2xw)^{5}*2 x^{2} } \\ \\ =2xw* \sqrt[5]{2x^{2} } ](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B64%20x%5E%7B7%7D%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B6%7D%20%20x%5E%7B7%7D%20%20w%5E%7B5%7D%20%7D%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282%29%5E%7B5%7D%2A2%2A%20x%5E%7B5%7D%2A%20x%5E%7B2%7D%20%2A%20w%5E%7B5%7D%20%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%20%282%5E%7B5%7D%20%20x%5E%7B5%7D%20%20w%5E%7B5%7D%20%29%2A2%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B5%5D%7B%282xw%29%5E%7B5%7D%2A2%20x%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D2xw%2A%20%5Csqrt%5B5%5D%7B2x%5E%7B2%7D%20%7D%20%0A%20)
Answer:
9.1
Step-by-step explanation:
The lower quartile, denoted as Q1, gives the value of the lower quartile, from a box plot, the value of the lower quartile is the value at the starting point of the box. In the box plot given for the windspeed in Chicago, the starting point of the box is the point marked with the reading 9.1. Hence we can conclude that the lower quartile is 9.1
To show that they used the same amount of ribbon you could take the 1 yard and divided into different sized equal groups.
1 yard divided by four equals 1/4 yard for each of four ribbons.
1 yard divided by six equals 1/6 yard for each of six ribbons.
You could have ribbons the size of 1/4 our yard and 1/6 yard, but you would have different amounts of each.
Answer:
h = 12x^5y^3
Step-by-step explanation:
The area of a parallelogram is found using A = b*h. Substitute the values given and solve for h.
A = b*h
36x^6 y^5 = 3xy^2 * h
36x^6 y^5 ÷ 3xy^2 = h
12x^5y^3 = h
y = x^2 -4x
x = -1
y = (-1)^2 - 4×-1=1+4 = 5
x= 0
y = (0)^2 - 4×0 = 0
x = 1
y = 1^2 -4×1 = 1-4 = -3
x = 2
y = 2^2 -4×2 = 4-8 = -4
x=3
y = 3^2 - 4×3 = 9-12 = -3
x = 4
y = 4^2 - 4×4 = 16 - 16 = 0
now 2nd equation
y = 2x^2 + x
x = -2
y = 2 (-2)^2 + (-2)= 8-2 = 6
x = -1
y = 2 (-1)^2+(-1)= 2-1 = 1
x = 0
y = 2(0)^2 +0 = 0
x = 1
y = 2 (1)^2 + 1 = 3
x = 2
y = 2(2)^2+2= 8 + 2 = 10
