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3 years ago

Find the GCF of each expression. Then factor the expression.

1 answer:

3 0

For finding GCF, just find the least number among them.
For example:
a.) 6x^2 - 9 find what number that can be divided to 6. In this case, it is 2 and 3.
You can't divide 9 by 2 so the answer in this equation would be 3.

b.) 2a^ 2 + 22a + 60 I's just the same method to use. In this case, we will use 2a^2. The factors that can be divided to 2 is (2,1). So we will choose 2 because it is the GCF of 2 and the equation is divisible by 2.

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Write the equation of the line that is parallel to the line and through the given point y=-2x+1 point (0,5)

marysya [2.9K]

Answer:

y = -2x+5

Step-by-step explanation:

y = -2x+1 is in the form y= mx+b where m is the slope and b is the y intercept

-2 is the slope

Parallel lines have the same slope so our new line will have the same slope

y = -2x+b

The point given is the y intercept (value when x is zero)

b = 5

y = -2x+5

5 0

3 years ago

What is it quick. And drop y’all Insta ask more

Tcecarenko [31]

Answer:

225 m2

Step-by-step explanation:

area= side*side

= 15x15

225 m2

4 0

3 years ago

2(x+5)=3x+1 x = ?<br><br> what is x?

Over [174]

2(x+5)=3x+1
*solving*
X = 9

7 0

3 years ago

Read 2 more answers

Find the equation of a line that passes through (-5,4) and us parallel to y=-6/7x+3

irina [24]

Given:

The given equation of line is

$y=-\dfrac{6}{7}x+3$

To find:

The equation of line that passes through (-5,4) and is parallel to the given line.

Solution:

Slope intercept form of a line is

$y=mx+b$ ...(i)

where, m is slope and b is y-intercept.

We have,

$y=-\dfrac{6}{7}x+3$ ...(ii)

On comparing (i) and (ii), we get

$m=-\dfrac{6}{7}$

Slope of given line is $m=-\dfrac{6}{7}$ .

Slope of parallel lines are same. So, slope of parallel line is $m=-\dfrac{6}{7}$ .

The required line passes through (-5,4) with slope $m=-\dfrac{6}{7}$ . So, the equation of line is

$y-y_1=m(x-x_1)$

$y-4=-\dfrac{6}{7}(x-(-5))$

$y-4=-\dfrac{6}{7}(x+5)$

$y-4=-\dfrac{6}{7}x-\dfrac{30}{7}$

Adding 4 on both sides, we get

$y=-\dfrac{6}{7}x-\dfrac{30}{7}+4$

$y=-\dfrac{6}{7}x+\dfrac{-30+28}{7}$

$y=-\dfrac{6}{7}x-\dfrac{2}{7}$

Therefore, the correct option is a.

8 0

3 years ago

The vertices of ΔABC are (-2,0), (-2, 3), and (-5, 1). T(x,y) = (x + 1, 3y) represents the transformation of the triangle. What

Gnoma [55]

using the equation for the transformation:

(x+1, 3y)

add 1 to very X and multiply y by 3

so (-2,0) becomes (-1,0)

(-2,3) becomes (-1,9)

(-5,1) becomes (-4,3)

new coordinates are (-1,0) (-1,9) (-4,3)

you don't have an image attached, so to see if they are congruent, the sides need to stay the same lengths and the angles need to stay the same, from the coordinates of the new triangle, I would say they are not congruent

8 0

3 years ago