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Ymorist [56]
3 years ago
13

A box is dragged 16 m across a level floor by a 25-N force at an angle of 45° to the floor. It is then dragged by

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

<u>solution</u>

W=f×d×cos theta

=25N×16m×cos 45°

=400Nm×cos 45°

=282.84J

W=f×d×cos theta

=25N×7m×cos 10°

=175Nm×cos10°

=172.34J

Total workdone=282.84J+172.34J=455.18J

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A.  y  = \frac{-5x}{2} - 1

Step-by-step explanation:

Given parameters:

Equation of the line:

       5x + 2y = 12

Coordinates = -2, 4

Unknown:

The equation of the line parallel to this line = ?

  • To solve this problem, first, we need to find the slope of the given line.

     Every linear equation have the formula:  y = mx + c

     m is the slope of the line, c is the y- intercept

           5x + 2y = 12

 Express this equation as y = mx + c

                 2y = -5x + 12

                    y = \frac{-5}{2}x  + 6

The slope of this line is \frac{-5}{2}

  • Now, any line that is parallel to another will not cut or cross it at any point. This simply implies they have the same slope.

                  Slope of the line parallel is \frac{-5}{2}

  • Our new line will also take the form y=mx + c,

          Coordinates = -2, 4, x = -2 and y = 4

                     m is \frac{-5}{2}

Now let us solve for C, the y-intercept;

                     4 = - 2 x \frac{-5}{2}  + C

                      4 = 5  + C

                       C = -1

The equation of the line is therefore;

                 y  = \frac{-5x}{2} - 1

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