Ask question

Ask question

All categories

3 years ago

14

There are 90 fifth-grade students going on a field trip. Each student gives the teacher $9.25 to cover admission to the theater

and for lunch. Admission for all of the students will cost $315, and each student will get an equal amount to spend on lunch. How much will each fifth grader get to spend on lunch?

2 answers:

nika2105 [10]3 years ago

3 0

There are 90 fifth-graders, and each student gives the teacher $9.25.

9.25 × 90 = 832.5

They gave a total of $832.50 to the teacher.

Admission for all of the students will cost $315

832.50 - 315 = 517.5

They have $517.50 left over for lunch.

Each student will get an equal amount of $ to spend on lunch.

517.50 ÷ 90 = 5.75

Each student will get $5.75.

Citrus2011 [14]3 years ago

3 0

Each fifth-grader student will spend $5.75 on lunch.

<h3>Further explanation </h3>

<u>Given:</u>

Number of students = 90 students

Each student gives $9.25 for admission and lunch

Admission for all students = $315

Each student will get an equal amount to spend on lunch.

<u>Question:</u>

How much will each fifth grader get to spend on lunch?

First step, we need to calculate the total amount the students gave to the teacher for admission and lunch

$\boxed {90 \times 9.25 = 832.5}$

then we will calculate the total amount for lunch

$\boxed {832.5 - 315 =517.5 }$

that is the total amount for lunch for all the students. To calculate how much each student get spend on lunch

$\boxed {= \frac{517.5}{90} }\\\boxed {= 5.75 }$

So, each student wil get $5.75 to spend on lunch.

<h3 /><h3>Learn more</h3>

Decimal number additional brainly.com/question/2013122

Total spend brainly.com/question/12203917

Decimal number multiplication brainly.com/question/2124592

Keywords: multiplication, decimal multiplication, two digits number additional, additional, subtraction decimal, regrouping

You might be interested in

A certain fraction has a value of 15. the denominator is four more than three times the numerator. what is the fraction?

ra1l [238]

N/d = 15
d= 4 + 3n

d=n/15
n/15=4+3n
n=60+45n
44n=-60
n=-15/11
-15/11 / d = 15
-15/11 = 15d
d=-1/11

15/11 / 1/11. = 15

3 0

3 years ago

Determine whether the given value is a solution of the equation.<br> 7w = 73; w = 10

kipiarov [429]

Step-by-step explanation:

When w=10, 7w=7×10=70

But the given value of 7w is 73.

So, the given value is not a solution of the equation.

8 0

3 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

PPLZ HURRY WILL MAK BRAINLIEST

zheka24 [161]

The answer is D because if you add all the same terms you get the answer

7 0

3 years ago

Read 2 more answers

Antoine works in a restaurant and he is paid his regular hourly rate of 40 hours a week and time and a half for all hours over 4

Inessa05 [86]

560+ 147= 707

14(40)= 560
14+ 14(1/2)=21
21(7)= 147

6 0

3 years ago