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motikmotik
3 years ago
6

Y´+2xy=0 C(e) C(0)=10 y=C(x)

Mathematics
1 answer:
zlopas [31]3 years ago
7 0
Your answer would be 120
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Molly needs to classify the triangle below based on angles. Which class is correct? 60° 50° 70° A. acute triangle О B. isosceles
Art [367]

Answer:

A. Actute triangle

Step-by-step explanation:

Is A because an acute triangle is a triangle where all the angles are the same.

Can not be B. because isosceles triangles have two sides that are the same which doesn't relate to angles.

Can not be C. because equilatiral triangles are triangles with sides that are all the same.

Can not be D. because for a triangle to be obtuse one of the angles needs to be greater that 90 degrees.

So it has to be A.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge
BabaBlast [244]

\underline{\bf{Given \:equation:-}}

\\ \sf{:}\dashrightarrow ax^2+by+c=0

\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.

\sf We\:know,

\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}

\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}

\underline{\large{\bf Identities\:used:-}}

\boxed{\sf (a+b)^2=a^2+2ab+b^2}

\boxed{\sf (√a)^2=a}

\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}

\boxed{\sf \sqrt{\sqrt{a}}=a}

\underline{\bf Final\: Solution:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}

\bull\sf Apply\: Squares

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}

\bull\sf Put\:values

\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}

\bull\sf Simplify

\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}

\underline{\bf More\: simplification:-}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}

\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}

\underline{\Large{\bf Simplified\: Answer:-}}

\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}

5 0
2 years ago
Read 2 more answers
Convert 300 g into kilograms
babymother [125]
300 grams = 0.3 kilograms
6 0
3 years ago
What number is equivalent to the fraction 8/9?
Marizza181 [45]

Answer:

0.88888889, 88.888889%,

Step-by-step explanation:

Convert to decimal, and convert decimal to percentage.

5 0
3 years ago
Robert is traveling to Mexico for a family vacation. He is bringing 625 U.S. dollars with him. Robert needs to exchange his mone
Evgesh-ka [11]

Robert should get D. 8281.25 pesos in exchange.

Explanation:

  • Robert is bringing 625 U.S. dollars with him to Mexico. He needs to exchange the money he has with him to Mexico's currency i.e. from U.S. dollars to Mexican pesos.
  • The exchange rate is 13.25 Mexican pesos for each U.S. dollar. So                               1 U.S. dollar = 13.25 Mexican pesos.
  • So to calculate how much 625 U.S. dollars is in pesos we multiply 625 with the exchange rate i.e. 13.25 pesos                                                        625 U.S dollars = 625 × 13.25 = 8281.25 Mexican pesos.

7 0
3 years ago
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