Question

Solve each system by substitution 14x-35=7y -25-6x=5y

Answer 1

Answer:

The solution of the system will be:  $x=0, y= -5$

Step-by-step explanation:

The given system of equation is......

$14x-35=7y ...................................(1)\\ \\ -25-6x=5y..................................(2)$

First, solving for $y$ in the equation (1) ........

$\frac{14x-35}{7}= \frac{7y}{7} \\ \\ y=2x-5$

Now, substituting this $y=2x-5$ into equation (2), we will get........

$-25-6x=5(2x-5)\\ \\ -25-6x=10x-25\\ \\ -25+25=10x+6x\\ \\ 0=16x\\ \\ x=\frac{0}{16}=0$

Plugging $x=0$ into $y=2x-5$, we will get.......

$y=2(0)-5= -5$

So, the solution of the system will be:  $x=0, y= -5$