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sweet-ann [11.9K]
3 years ago
11

a solid circular cylinder of radius 7 cm and length 8 cm is made out of metal alloy. given that 1 cm³ of the alloy has a mass of

5 g , find the mass, in grams, of the cylinder
Mathematics
1 answer:
amid [387]3 years ago
7 0
The problem is to find a mass of cylindrical solid given its dimensions and the density of the solid. Density is defined as mass per volume of substance, therefore to find the mass, the volume of the solid must be known. Volume of cylinder = (PI) (r^2) h = (PI) (7^2) (8) = 1231.5043 cm^3 Using the density: Mass = (5 g/ 1 cm^3)( 1231.5043 cm^3) = 6157.5216 g
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Please answer with explanation
nalin [4]

Answer:

(a)- 2 [ ( - \frac { 1 } { 4 } ) - 12 ( - 1 ) ^ { 2 } ] - 5 [ 24 + 2 ( - 12 ) ] ^ { 2 }−2[(−

4

1

)−12(−1)

2

]−5[24+2(−12)]

2

Do the arithmetic.

Calculate -1−1 to the power of 22 and get 11.

-2\left(-\frac{1}{4}-12\right)-5\left(24+2\left(-12\right)\right)^{2}−2(−

4

1

−12)−5(24+2(−12))

2

Subtract one term from another.

Subtract 1212 from -\frac{1}{4}−

4

1

to get -\frac{49}{4}−

4

49

.

-2\left(-\frac{49}{4}\right)-5\left(24+2\left(-12\right)\right)^{2}−2(−

4

49

)−5(24+2(−12))

2

Multiply two factors together.

Multiply -2−2 and -\frac{49}{4}−

4

49

to get \frac{49}{2}

2

49

.

\frac{49}{2}-5\left(24+2\left(-12\right)\right)^{2}

2

49

−5(24+2(−12))

2

Multiply two factors together.

Multiply 22 and -12−12 to get -24−24.

\frac{49}{2}-5\left(24-24\right)^{2}

2

49

−5(24−24)

2

Subtract one term from another.

Subtract 2424 from 2424 to get 00.

\frac{49}{2}-5\times 0^{2}

2

49

−5×0

2

Multiply two factors together.

Multiply 55 and 00 to get 00.

\frac{49}{2}-0

2

49

−0

Add two terms together.

Subtract 00 from \frac{49}{2}

2

49

to get \frac{49}{2}

2

49

.

\frac{49}{2}

2

49

2

49

=24.5

(b)−a

2

b

2

−3a

3

b

2

a=−

3

1

b=−1

Step-by-step explanation:

Hope it helps u

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Answer:

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Step-by-step explanation:

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