This is a differential equations problem. We are to work backwards and determine the function f(x) when given f "(x) and initial values.
<span>f ''(x) = 12x^2 + 6x − 4, when integrated with respect to x, yields:
x^3 x^2
f '(x) = 12------ + 6----- - 4x + C, or 4x^3 + 3x^2 - 4x + C, and
3 2
x^4 x^3 x^2
f(x) = 4------- + 3------- - 4------ + Cx + D, or f(x)=x^4 + x^3 - 2x^2 + Cx + D
4 3 2
Now, because f(0)=5, 5=0^4 + 0^3 -2(0)^2 + C(0) + D, so that D=5.
Determine D in the same manner: Let x=1 and find the value of C.
Then the solution, f(x), is x^4 + x^3 - 2x^2 + Cx + 5. Replace C with this value and then you'll have the desired function f(x).</span>
Answer:
-5x-3y^3
Step-by-step explanation:
x-3y^3+3x^3-5x-x^3-x-2x^3
Answer:
Point M
Step-by-step explanation:
Your answer is C) 1/9
lol I just solved the other answer sorry but people are going to try and take free points so I needed to give an answer to show that someone did something. Hope I helped anyway. You don't need to mark brainliest, but I'd appreciate it if you did.
<h2>-^_^-</h2>
Answer:
x₁ = -4
x₂ = 3
Step-by-step explanation:
x²+ x + 12 = 0
x = {-1±√((1²)-(4*1*-12))} / (2*1)
x = {-1±√(1+48)} / 2
x = {-1±√49} / 2
x = {-1±7} / 2
x₁ = {-1-7} / 2 = -8/2 = -4
x₂ = {-1+7} / 2 = 6/2 = 3
Check:
x₁
-4² + (-4) - 12 = 0
16 - 4 - 12 = 0
x₂
3² + 3 - 12 = 0
9 + 3 - 12 = 0
