Answer:
In a STAR TOPOLOGY network, each device on the network is attached to a central router. If the router fails, then the other devices will be unable to communicate, but if only one connected device fails, then all other devices will still be able to communicate.
Explanation:
In this type of topology all the computers are connected to a single router through a cable. This router is the central node and all others nodes are connected to the central node.
Answer:
By modifying the hidden form values that is in a local copy of the company web page
Explanation:
In a situation were the hacker successful change the price of the items he/she purchased through the web site of the company's in which the company web server as well as the company Oracle database were not compromised directly which means that the most likely method in which the attacker used to modified the sale price of the items he/she purchased was by modifying the HIDDEN FORM VALUE that was in the local copy of the company web page making it easy for the HIDDEN FORM VALUE to be vulnerable to the hacker because the hidden form value did not store the company server side information or data but only store the company software state information which is why HIDDEN FORM VALUE should not be trusted.
Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
Answer:
All of the above but I'm not 100% sure.
