1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marysya12 [62]
2 years ago
12

In the diagram AB is parallel to CD. What is the term for the line that intersects the two parallel lines? A) transversal B) per

pendicular C) normal D) bisector​

Mathematics
1 answer:
Alex73 [517]2 years ago
6 0

Answer:

  A) transversal

Step-by-step explanation:

The vocabulary term you're looking for is "transversal."

A transversal crosses parallel lines (or ones that are nearly parallel in the vicinity of the transversal).

You might be interested in
40% of 80 <br> What’s for this Question
natta225 [31]

Answer:32

Step-by-step explanation:

80x.40=32

3 0
3 years ago
Read 2 more answers
Factor the polynomial
QveST [7]
Wheres the polynomial
4 0
3 years ago
ANYONE PLEASE HELP ME WITH MY MATH HOMEWORK I REALLY NEED THE ANSWER RIGHT NOW BECAUSE I HAVE TO PASS THIS TOMORROW I HOPE Y'ALL
Eddi Din [679]

Hope these images helps you...

AnswerEd by Benjemin ☺️

4 0
2 years ago
A student researcher compares the heights of men and women from the student body of a certain college in order to estimate the d
maria [59]

Answer:

(0.6613, 8.3387)

Step-by-step explanation:

Let the heights of men be the first population and the heights of women be the second population. Then

We have n_{1} = 15, \bar{x}_{1} = 69.4, s_{1} = 3.09 and

n_{2} = 7, \bar{x}_{2} = 64.9, s_{2} = 2.58. The pooled

estimate is given by  

s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(15-1)(3.09)^{2}+(7-1)(2.58)^{2}}{15+7-2} = 8.68

The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{15}+\frac{1}{7}}, i.e.,

(69.4-64.9)\pm t_{0.005}2.946\sqrt{\frac{1}{15}+\frac{1}{7}}

where t_{0.005} is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So  

4.5\pm(-2.845)(2.946)(0.458), i.e.,

(0.6613, 8.3387)

5 0
3 years ago
How do I solve this equation????
Alexus [3.1K]
So for this question (for finding x and y) you will want to use elimination. To do this you will need to bring the x and y to the same side (I put them on the left):
-3/2x+y=6
x+y=0
Now subtract the y on the bottom from the top to isolate x:
3/2x=6
Now the easiest way to bring over the 3/2 to isolate the x fully is to convert it to decimal (1.5) and divide it by 6 (because when multiplication on one side of problem the only way to bring it over is to divide):
x=6/1.5
which simplifies to: 
x=4
Hope this helps!
4 0
3 years ago
Other questions:
  • 9 and 9/10 as a decimal
    14·2 answers
  • The box y contains 5 red blocks and 7 blue blocks. What fraction of all blocks are red?
    9·1 answer
  • 0.5 kilograms (kg) is equal to how many ounces? Round your answer to the nearest tenth.
    12·2 answers
  • help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    12·2 answers
  • The sum of two numbers is 54 and the difference is 18 . what are the numbers
    12·1 answer
  • Solve the inequalities, if possible, and graph. 4(4t + 2) &lt; 2(4t + 4).
    8·1 answer
  • You are given two sides of a triangle, a = 3.5 and b = 5.2. the angle between them is 37 degrees. write a script to find the len
    11·1 answer
  • Each year the local country club sponsors a tennis tournament.Play starts with 128 participants.During each round,half of the pl
    8·1 answer
  • mrs baxter deposits $2,000 in an account that earns 5% simple interest.How much is mrs baxter's investment worth after eight yea
    14·1 answer
  • The rectangle below has an area of 30k3 + 6k2.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!