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Vilka [71]
4 years ago
11

8 div by 275 place 0 in qoutient

Mathematics
1 answer:
Norma-Jean [14]4 years ago
5 0
275 divided by 8 is <span>34.375</span>
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Rashad compiled a list of fixed expenses and noted his total expenses for last month.
Digiron [165]

The equation that represents the variable expences for the february is

x+ $1943.48 = $3,291.74

The linear equation is an equation where highest degree of the variables is 1.

As we know Total expenses include fixed as well as variable expenses.

Total Expenses = Variable Expenses +Fixed Expenses

⇒ Variable Expenses = Total Expenses - Fixes Expenses

Hence to Determine variable expenses Rashad needs we have to subtract his fixed expenses from his total expenses for the month.

Here, given that all February fixed expenses amount are

For rent, expenses are $1,150.00

For car loan expenses are $348.00

For internet, expenses are $46.14

For a student loan, expenses are $399.34

So the total amount of fixed expances are= rent expences+ car loan expences+ internet expences+ student loan expences = $1150+ $348+ $46.14+ $399.34 =$1943.48

Given, The total February expanses are $3,291.74.

Let;s assume the variable expenses is x

As we know

Total Expenses = Variable Expenses +Fixed Expenses

Then the linear equation will be

⇒ x+ $1943.48 = $3,291.74

solving for x i.e. Variable Expenses =  $3,291.74-$1943.48

⇒ Variable Expenses =  $1348.26

Therefore The equation that represents the variable expences for the february is   x+ $1943.48 = $3,291.74

Learn more about the linear equation

here: brainly.com/question/2030026

#SPJ10

7 0
2 years ago
Evaluate the function below for f(3)<br> f (x) = 3x2 - 5<br> what’s the answer
Novay_Z [31]
The answer is 13 because you would plug in 3(3) which is 9 then you multiply (9)(2) which is 18 they you subtract 18-5 which equals 13
4 0
3 years ago
Sorry this is the last question...
MrRa [10]
19/20 / 1/2 I hope this helps
5 0
3 years ago
Read 2 more answers
How do I simply this, thanks!
stepan [7]
(-a^3b^2*-a^-2b^-3)^-2/2a^2b^-3 = a^4b^9/2a^8b^4 =b^5/2a^4 so your answer is b^5/2a^4
7 0
3 years ago
Using the quadratic formula to solve 5x=6x squared -3, what are the values of x?
kiruha [24]
Answer: 5+sqrt(97)/12, 5-sqrt(97)/12 or we write it as [5+/-sqrt(97)]/(12)

5x=6x^2-3

6x^2-5x-3=0

x=-b+/-sqrt(b^2-4ac)/2a

x=-(-5)+/-sqrt((-5^2-4(6)(-3))/2(6)

x= 5+/-sqrt(97)/12

And decimal form is;

x=1.237, -0.4041

If anyone has any questions please feel free to ask and I’ll reply ASAP. Thanks
7 0
4 years ago
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