Answer:
1) 3( 2) - 1 = 6 - 1 = 5
2) 2(-1) - 3+4(-1) = -2 -7 = -9
3) 4^2-6(4)=9 = 16-24=9, = -8=9
Answer is 30
you can use PEMDAS to help you on further questions like this
P-Parenthesis
E-Exponents
M/D-Multiplication/Division solved in order from left to right
A/S-Addition/Subttaction solved in order from left to right
The answer is 45.
15% = 0.15, since you move the decimal 2 places
0.15 x 300 = 45.
Answer: 24, 33
2.5, 4.75
9.5, 11.75
<u>Step-by-step explanation:</u>
It is given that the PERIMETER is BETWEEN 24 and 33
--> 24 < P < 33
Graph: O------------------O
24 33
Perimeter = 2w + 2L
It is given that L = w + 7
Substitute P with 2w + 2L and substitute L with w + 7
24 < 2w + 2(w + 7) < 33
24 < 2w + 2w + 14 < 33
10 < 4w < 19
--> 2.5 < w < 4.75
Graph: O--------------------------O
2.5 4.75
Since L = w + 7, then w = L - 7
Substitute P with 2w + 2L and substitute w with L - 7
24 < 2(L - 7) + 2L < 33
24 < 2L + 2L - 14 < 33
38 < 4L < 47
--> 9.5 < L < 11.75
Graph: O------------------------O
9.5 11.75
<em>NOTE: Make sure you use OPEN dots on the graphs.</em>
Answer:
The volume of foam needed to fill the box is approximately 2926.1 cubic inches.
Step-by-step explanation:
To calculate the amount of foaming that is needed to fill the rest of the box we first need to calculate the volume of the box and the volume of the ball. Since the box is cubic it's volume is given by the formula below, while the formula for the basketball, a sphere, is also shown.
Vcube = a³
Vsphere = (4*pi*r³)/3
Where a is the side of the box and r is the radius of the box. The radius is half of the diameter. Applying the data from the problem to the expressions, we have:
Vcube = 15³ = 3375 cubic inches
Vsphere = (4*pi*(9.5/2)³)/3 = 448.921
The volume of foam there is needed to complete the box is the subtraction between the two volumes above:
Vfoam = Vcube - Vsphere = 3375 - 448.921 = 2926.079 cubic inches
The volume of foam needed to fill the box is approximately 2926.1 cubic inches.
