All categories

2 years ago

Kevin has traveled 42, 1/2 miles on his trip. That is 1/3 of the total distance, how far is his trip?

Mathematics

1 answer:

sergiy2304 [10]2 years ago

5 0

42 and a half right?

multiply it by 3 and you get 127 and a half

You might be interested in

Identify equal rational numbers in this list: <br><br> (The fractions)

Pachacha [2.7K]

Answer:

All of them

Step-by-step explanation:

A rational number is any number that can be written as a fraction.

hope this helps :)

3 0

2 years ago

To investigate whether or not people tend to marry spouses of similar ages or whether husbands tend to be older than their wives

ira [324]

Answer:

See explanation below

Explanation:

1) Option C is correct.

The average difference in husband and wife marriage ages in Cumberland County; μd

2) Option D is correct.

Null: The average difference in marriage ages in Cumberland County is 0.

Alt: The average difference in marriage ages is greater than 0.

3) Option A is correct

Null: μd = 0

Alt: μd > 0

4) Given:

n = 24

d' = 1.875

Sd = 4.812

Find test statistic:

$t = \frac{d'}{Sd/\sqrt{n}}$

$= \frac{1.875}{4.812/\sqrt{24}}$

$t = 1.909$

Degree of freedom, df = n - 1 = 24 - 1 = 23

Pvalue $= (t_2_3 > 1.909) = 0.0344$

Pvalue = 0.0344

Significance level = 0.05

5) Since p value is less than significance level, reject null hypothesis H0

Hence, there is strong evidence that, on average, husbands are older than their wives in Cumberland County

5 0

2 years ago

The average radius of Jupiter is 4.34 x 10^4 miles. The average sun radius of the sun is 4.32 x 10^5. How many times greater is

Oksanka [162]

Answer:

The average radius of sun is approximately 9.95 times the average radius of Jupiter.

Step-by-step explanation:

We are given the following in the question:

Average radius of Jupiter =

$4.34\times 10^{4}\text{ miles}$

Average radius of the sun =

$4.32\times 10^{5}$

Relation between average radius of sun and average radius of Jupiter =

$\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}}\\\\= \frac{4.32\times 10^{5}}{4.34\times 10^{4}}\\\\\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}} = 9.953917\\\\\text{Average radius of Sun} \approx 9.95\times \text{(Average radius of Jupiter)}$

Thus, the average radius of sun is approximately 9.95 times the average radius of Jupiter.

7 0

3 years ago

Please help me!! matrices question! ASAP

katrin2010 [14]

5 possibly cause the state of numbers have a typical pattern! NOT SURE THO!!! but a little help! <3 goodluck.

4 0

1 year ago

Lena [83]

The answer is 30 I believe

7 0

2 years ago

Read 2 more answers