Answer:
a) 22.8%
Step-by-step explanation:
(2590-2000) ÷ 2590 =
590 ÷ 2590 =
.2277 = 22.8%
Answer: The answer to that would be 4/5= 32/40.
Step-by-step explanation: It is 4/5 =32/40 because if you were to divide the 40 by the 5 you would get 8. Since you got 8 when dividing 40 by 5 you would multiply 8x4. You would do this because whatever you do to the denominator you would do to the numerator. So you would multiply 4/5 x 8/8 and get 32/40. PLEASE MARK BRAINLIEST!!!!
Answer:
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Step-by-step explanation:
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The goal here is to find the cost of the painting BEFORE the 60% increase.
To find the cost of the painting, we must take in the information we already have:
Increase percent: 60%
Original price: unknown
Price after increase: $400
$400 is the price of the painting AFTER the increase has been added. So this equals the cost of the painting before the increase, plus the total amount of the increase (which is 60% of the original price).
The total must be (100% + 60% = 160%) 160% of the original painting price.
To find the original price, we must divide the increased price by the new percentage (160%). But how do we get here?
Well, we have 160% and our (fraction) $400/1%. We will have to switch the 160% and the 1%, giving us..
1% $400/160%
We take 400/160, which is 2.5. But this is only 1% of the original price! We want 100%.
So now, we multiply the 2.5 by 100 to get our answer: $250.
I hope this helps! If you have any questions, feel free to ask.
Answer:
a. The sampling distribution for the sample mean will be skewed to the left centered at the average u, and standard deviation will be ∅
b. The sample distribution will be normal in shape and will be centered at the average u, . standard deviation will be ∅1
c. As the size of the sample increases, the sample distribution should draw near and resemble the distribution of the population
Step-by-step explanation:
A sample is chosen randomly from a population that was strongly skewed to the left. a) Describe the sampling distribution model for the sample mean if the sample size is small. b) If we make the sample larger, what happens to the sampling distribution model’s shape, center, and spread? c) As we make the sample larger, what happens to the expected distribution of the data in the sample?
The following answers will march the questions above:
a. The sampling distribution for the sample mean will be skewed to the left centered at the average u, and standard deviation will be ∅
b. The sample distribution will be normal in shape and will be centered at the average u, . standard deviation will be ∅1
c. As the size of the sample increases, the sample distribution should draw near and resemble the distribution of the population