Question

Given: bisects ∠BAC; AB = AC Which congruence theorem can be used to prove △ABR ≅ △ACR?

Answer 1

Answer: SAS

Step-by-step explanation:

Here ABC is a triangle, In which angle BAC is bisected by line AR where, $R\in BC$ .

Thus in triangles ABR and ACR,

AB= AC ( given)

Therefore $AB\cong AC$

$\angle BAR\cong \angle CAR$ ( by the property of angle bisector)

And,    $AR\cong AR$   (reflexive)

Thus by SAS postulate,

△ABR ≅ △ACR.

Therefore, Option D is correct.

Answer 2

Answer:

The answer is SAS

Step-by-step explanation:

I got it right on edge