1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anvisha [2.4K]
2 years ago
6

PLEASEEEE HELP !!!!!!!!!!!!!!!!! Abanoub is using a machine to drill for oil that is 535 feet under the ground. The drill he is

using is drilling at a rate of -35 feet per hour. How long did it take him to reach the oil? a 15.28 Hours b - 15.28 Hours c 18,725 Hours d -18,725 Hours
Mathematics
1 answer:
In-s [12.5K]2 years ago
4 0

Answer:

a) 15.28 hours

Step-by-step explanation:

535/-35

≈-15.28

but time is always positive so it would take him 15.28 hours

You might be interested in
Somebody please help me with my geometry.
eduard

Answer:

In order to read the degrees of an angle with a protractor, you must first determine if the angle is acute or obtuse. If it is acute, you use the measurement of the smaller number on the protractor. If it is obtuse, you use the larger measurement on the protractor.

For example, the measurement of the angle in question 1 seems to be about 74 degrees.

4 0
2 years ago
Charlie had a full bottle of water. He drank 1/4 of the water in the morning. He drank 2/5 of the water with lunch. How much of
12345 [234]

Answer:

7/20

Step-by-step explanation:

first of all you have to put the two fractions on the same denominators

1/4 (multiply by 5) and you will get 5/20

2/5(multiply by 4) and you will get 8/20

we have to add 5/20 and 8/20 that gives us 13/20

13/20 is the amount he drank

20/20 - 13/20 =7/20

7/20 is the amount of water left that Charlie has left

3 0
2 years ago
Angle relationships worksheet #2 10-17
lbvjy [14]

That does not make any since...

3 0
3 years ago
PLEASE ANSWER EACH OF THESE QUESTIONS IM GIVING OUT BRAINLIEST !!!!! D:
Alexus [3.1K]

Answer:

no 1

2x^2 + 6

no 2

x^2 + 63

no3

2x^2 + 20

no 4

3 x 3 x 4 divided by 3

=12cm^3

3 0
2 years ago
Read 2 more answers
An urn contains n white balls andm black balls. (m and n are both positive numbers.) (a) If two balls are drawn without replacem
Genrish500 [490]

DISCLAIMER: Please let me rename b and w the number of black and white balls, for the sake of readability. You can switch the variable names at any time and the ideas won't change a bit!

<h2>(a)</h2>

Case 1: both balls are white.

At the beginning we have b+w balls. We want to pick a white one, so we have a probability of \frac{w}{b+w} of picking a white one.

If this happens, we're left with w-1 white balls and still b black balls, for a total of b+w-1 balls. So, now, the probability of picking a white ball is

\dfrac{w-1}{b+w-1}

The probability of the two events happening one after the other is the product of the probabilities, so you pick two whites with probability

\dfrac{w}{b+w}\cdot \dfrac{w-1}{b+w-1}=\dfrac{w(w-1)}{(b+w)(b+w-1)}

Case 2: both balls are black

The exact same logic leads to a probability of

\dfrac{b}{b+w}\cdot \dfrac{b-1}{b+w-1}=\dfrac{b(b-1)}{(b+w)(b+w-1)}

These two events are mutually exclusive (we either pick two whites or two blacks!), so the total probability of picking two balls of the same colour is

\dfrac{w(w-1)}{(b+w)(b+w-1)}+\dfrac{b(b-1)}{(b+w)(b+w-1)}=\dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

<h2>(b)</h2>

Case 1: both balls are white.

In this case, nothing changes between the two picks. So, you have a probability of \frac{w}{b+w} of picking a white ball with the first pick, and the same probability of picking a white ball with the second pick. Similarly, you have a probability \frac{b}{b+w} of picking a black ball with both picks.

This leads to an overall probability of

\left(\dfrac{w}{b+w}\right)^2+\left(\dfrac{b}{b+w}\right)^2 = \dfrac{w^2+b^2}{(b+w)^2}

Of picking two balls of the same colour.

<h2>(c)</h2>

We want to prove that

\dfrac{w^2+b^2}{(b+w)^2}\geq \dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

Expading all squares and products, this translates to

\dfrac{w^2+b^2}{b^2+2bw+w^2}\geq \dfrac{w^2+b^2-b-w}{b^2+2bw+w^2-b-w}

As you can see, this inequality comes in the form

\dfrac{x}{y}\geq \dfrac{x-k}{y-k}

With x and y greater than k. This inequality is true whenever the numerator is smaller than the denominator:

\dfrac{x}{y}\geq \dfrac{x-k}{y-k} \iff xy-kx \geq xy-ky \iff -kx\geq -ky \iff x\leq y

And this is our case, because in our case we have

  1. x=b^2+w^2
  2. y=b^2+w^2+2bw so, y has an extra piece and it is larger
  3. k=b+w which ensures that k<x (and thus k<y), because b and w are integers, and so b<b^2 and w<w^2

4 0
3 years ago
Other questions:
  • Classify the following expression by degree and term:x3y + 5xyz
    5·2 answers
  • Where is the removable discontinuity of f(x)=x+5/x^2+3x-10 located?
    8·2 answers
  • .<br> Please answer this correctly
    15·1 answer
  • What are the approximate solutions of 2x^2 - X + 10 = 0?
    11·1 answer
  • 20 people show up to a post-PSTAT 120A party. If everyone shakes hands with everyone else, how many handshakes take place
    13·1 answer
  • 22201+54633333333333
    9·1 answer
  • Two parallel lines are cut by a transversal as shown below.<br> Suppose
    9·2 answers
  • Ross and Ronnie are late for their favorite show . Ross walks around a rectangular park with dimensions of 150 ft by 215 ft. Ron
    10·1 answer
  • I need an answer as soon as possible
    7·2 answers
  • Show that P = 6x + 2
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!