<span>Her liabilities are her credit card bill and her car loan. These are things that she owes and has to pay off, so they are liabilities due to the fact that she owes for these items. Her bonds, piano, bank account, and bicycle are counted as assets.</span>
Answer:
Paragraph Styles and character formatting (font, color, etc.)
The answer is the team. Teams are self-establishing which no one not even the scrum master tells the team how to turn product backlog into augmentations of stoppable functionality. Each team member put on his or her knowledge to all of the complications. The interaction that outcomes progresses the entire scrum team’s general competence and usefulness. The optimal size for a scrum team is seven people, plus or minus two. When there are fewer than five team members, there is less interface and as a result less productivity improvement. The product owner and scrum master roles are not comprised in this count. Team arrangement may variation at the end of a sprint. Every time Team membership is altered, the productivity increased from self-organization is reduced.
The program is
num = int(input("Enter Numerator "))
den = int(input("Enter Denominator "))
print("quotient is ",str(num//den)," remainder is ", str(num%den))
<h3>
How to create a division sign in HTML?</h3>
To create a division sign ( ÷ ) in HTML you can use any of the following codes.
÷
÷
÷
<h3>
How to divide in computer programming?</h3>
Perl code
use strict;
my $first = 15;
my $second = 5;
my $answer = $first / $second;
print "You get $answer if you divide $first by $second";
When the script above is run, it displays "You get 3 if you divide 15 by 5" on the screen.
To learn more about programming, refer
https://brainly.ph/question/4743
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Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
