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slega [8]
3 years ago
15

How do I solve this?

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0
You should go to a tutoring site
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Please help me with my math question!!!
Ierofanga [76]

Answer:

2x^9(6x^3+x^2-4x+5x^-9)

Step-by-step explanation:

2x^9(6x^3+x^2-4x+5x^-9)

6 0
4 years ago
Two runners ran as a team in a 5,000-m relay race. the first runner ran 500 m farther than the second runner. how many meters di
hammer [34]
Let a = runner 2, a + 500 = runner 1.

a + (a + 500) = 5000
2a + 500 = 5000
2a = 4500
a = 2250

Runner 1 ran 2,750 meters. Runner 2 ran 2,250 meters.  
3 0
3 years ago
Read 2 more answers
A letter reaches a height of 16 feet on the wall. If the bottom of the ladder is placed 4 feet away from the wall, what is the s
Allushta [10]
16.492 /1 , using the Pythagorean theorum as a basis.
8 0
4 years ago
Which classification best describes ∠2?
just olya [345]
The angle is obviously larger than a right angle because it is bending outwards. This means it is greater than 90°, so ∠2 must be an obtuse angle.
4 0
4 years ago
Read 2 more answers
Given:<br> m∠LON=77 °<br> m∠LOM=9x+44 °<br> m∠MON=6x+3 °<br><br> Find ∠MON
NISA [10]

Answer:

m\angle MON=15^o

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m\angle LON=m\angle LOM+m\angle MON ---> by addition angle postulate

substitute the given values

77^o=(9x+44)^o+(6x+3)^o

solve for x    

77=(15x+47)

15x=77-47                                

15x=30\\x=2                                                

<em>Find the measure of angle MON   </em>

m\angle MON=(6x+3)^o      

substitute the value of x        

m\angle MON=(6(2)+3)=15^o                                                                        

8 0
3 years ago
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