1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pickupchik [31]
3 years ago
13

A school class went on a field trip to see a magician perform there were 17 females 20 males in the class the magicians randomly

selected a volunteer from the audience in which had 52 females and 68 males given that the randomly selected audience member is a student from the class which equation can be used to find the probability p that the perdimos also a female?please help does anyone know the answer
Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

P(B)= 17/20

Step-by-step explanation:

Hello!

The audience of the magic show is conformed by a total of 120 people, 52 of which are female and 68 are men.

Within the audience there is a school class of 37, of these students, 17 are female and 20 are male.

If a random member of the audience is selected as a volunteer:

Let "A" represent the event that "the selected volunteer is a student of the class"

And "B" the event that "the selected student is female"

You have to calculate the probability of the selected volunteer being female, given that it is a member of the school class.

Symbolically:

P(B|A)

Using the formula of conditional probabilities you can calculate it as:

P(B|A)= \frac{P(AnB)}{P(A)}

P(A∩B)= P(A)*P(B)= (\frac{37}{120} )*(\frac{17}{20} )= \frac{629}{2400}= 0.26

P(A)= \frac{37}{120} = 0.308

P(B|A)= \frac{P(AnB)}{P(A)}= \frac{629/2400}{37/120} = \frac{17}{20} = 0.85

As you can see the probability of the event "The volunteer is female given that it was a student of the school class" means that you already know the selected volunteer was a student and only needed to calculate the probability of that student being female.

P(B)= 17/20

I hope this helps!

You might be interested in
Renee hiked for 8 and 3/4 miles. After resting, Renee hiked back along the same route for 7 and 1/4 miles. How many more miles d
mart [117]
The answer is 3/2. you do this by subtracting 7 1/4 from the 8 3/4 and simplifying the 6/4!
6 0
3 years ago
I don't want the answer, I want to know how to do it. What is the ratio of 4/5 to 7/15?
Ostrovityanka [42]

Answer:

\displaystyle 1\frac{5}{7}

Step-by-step explanation:

\displaystyle \frac{4}{5} \div \frac{7}{15} = \frac{4}{5} \times \frac{15}{7} = \frac{60}{35} = 1\frac{5}{7}

I can assist whenever I can.

6 0
4 years ago
11/6 + -2/5 +-13/10?
Goshia [24]

Answer:

<h2><u><em>2/15 </em></u></h2>

<u><em></em></u>

<h2><u><em>Step-by-step explan</em></u>ation:</h2>

11/6 + -2/5 +-13/10?

11/6 + (-2/5) + (-13/10)

43/30 - 13/10

2/15

6 0
2 years ago
Just trying to pass math man
makkiz [27]
The answer is 3x^2 +3x
6 0
3 years ago
ppositional angle closure in eyes with narrow angles: comparison between the fellow eyes of acute angle-closure glaucoma and nor
skad [1K]

Here is the comparision

Purpose:To compare the topologic features of acute primary angle-closure glaucoma eyes before an attack to those of normotensive eyes, assuming that untreated fellow acute primary angle-closure glaucoma eyes are candidates for an acute attack.

Methods:Under dark-room conditions, ultrasound biomicroscopy was used to examine 50 eyes (12 fellow eyes of acute primary angle-closure glaucoma and 38 normotensive cases with a closure-possible narrow angle). Before any surgical or laser intervention, all eyes were examined and found to have normal pupillary response without the use of any topical drugs. Each eye was examined at four predetermined angle locations. The chamber angle configuration parameters were measured and compared between the two groups.

Result:Appositional angle closures were detected in 27 fellow eyes and 48 normotensive eyes with a closure-possible narrow angle. The incidence differed statistically between the two groups (69.2% in fellow eyes and 48% in normotensive eyes). In the fellow eye group, appositional angle closures beginning at the angle's entrance were more frequently detected. The distance between the iris root and the bottom of the angle varied significantly between groups.

Conclusion:Acute primary angle-closure glaucoma fellow eyes have different topologic features than normotensive narrow-angled eyes, as well as a higher incidence of appositional closure, which may predispose these eyes to an impending acute attack.

Learn more about glaucoma here:

brainly.com/question/1318395

#SPJ4

8 0
2 years ago
Other questions:
  • Miguel biked 14 km in the same amount of time that linda hiked 10 km. Miguel's rate was 4 km/h more than linda's. How fast did e
    15·1 answer
  • What is the Value of X?<br> 4x-4=4x
    15·1 answer
  • A student on the track team runs 45 minutes each day as a part of her training. She
    6·1 answer
  • Which term best describes a major arc of a circle that has the same starting and ending point
    7·2 answers
  • What equasion is equivilent to 7(x+4)? PLZZZZZZ
    10·2 answers
  • The Breyer twins split the cost of their purchase. They bought an aquarium for $28.00. They spent $14.00 on fish, and they spent
    8·1 answer
  • Points A and B are on the different sides of a line 1, the distance between point A and the line lis 10 in, the distance between
    13·1 answer
  • Kaio bought a meal in a town for $20. Sales tax was 6.5% and he left a 15% tip. What was the amount Kaio paid in sales tax?What
    5·1 answer
  • So I know that this isn’t the kind of app I should be speaking about my problems but I just want to burst out into tears from ho
    15·1 answer
  • 1/2 to the 2nd power in fraction form
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!