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2 years ago

12

A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle?

1 answer:

Alexxandr [17]2 years ago

7 0

Answer:

x^2+y^2=9^2

Step-by-step explanation:

The standard equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where the center of a circle is (h,k) and r is the radius of the circle. In this case because a circle is equidistant from the center and we have a point where it passes through 9 that means that the radius is 9. However, since the standard equation states that we must write r in the form of $r^2$ this means that $r^2=9^2$ . Therefore by plugging in the values we have:

$(x-0)^2+(y-0)^2=9^2\\\\x^2+y^2=9^2$

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Next year the price is going to be 10.23

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3 years ago

The red Maserati traveled at a speed of 120km/h for 5 hours one day. The green Ford Pickup traveled at a speed of 74km/h for 6 h

ehidna [41]

Answer:

156km

Step-by-step explanation:

Given data

The red Maserati traveled at a speed of 120km/h for 5 hours one day.

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3 years ago

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77julia77 [94]

Answer:

32

Step-by-step explanation:

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side 2 - 13 (9+3)

Triangle perimeter formula - a + b +c

13 + 6 + 13 = 32

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2 years ago

consider the rectangular prism shown. using only whole number dimensions, how many different prosms are possible?

Leviafan [203]

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3 years ago

Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $30,

REY [17]

Answer:

a) 217

b) 1351

c) 5403

Step-by-step explanation:

Given that:

confidence interval (c) = 0.95

$\alpha =1-0.95=0.05\\\frac{\alpha }{2} =\frac{0.05}{2}=0.025$

The Z score of $\frac{\alpha }{2}$ is from the z table is given as:

$Z_{\frac{\alpha }{2} }=Z_{0.025}=1.96$

Range = $45000 - $30000 = $15000

The standard deviation (σ) is given as:

$\sigma=\frac{Range}{4} =\frac{15000}{4}=3750$

Sample size (n) is given as:

$n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2$

a) E = $500

$n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{500} )^2$ ≈ 217

b) $n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{200} )^2$ ≈ 1351

c) $n=(\frac{Z_{\frac{\alpha}{2} }\sigma}{E} )^2= (\frac{1.96*3750}{100} )^2$ ≈ 5403

7 0

2 years ago

Read 2 more answers