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Gre4nikov [31]
3 years ago
12

A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle?

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

x^2+y^2=9^2

Step-by-step explanation:

The standard equation of a circle is:

(x-h)^2+(y-k)^2=r^2

Where the center of a circle is (h,k) and r is the radius of the circle.  In this case because a circle is equidistant from the center and we have a point where it passes through 9 that means that the radius is 9.  However, since the standard equation states that we must write r in the form of r^2 this means that r^2=9^2.  Therefore by plugging in the values we have:

(x-0)^2+(y-0)^2=9^2\\\\x^2+y^2=9^2

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Step-by-step explanation:

The area of a rectangle is Length x Height, or Width x Height.

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We multiple 5/6 and 11/12 to get 55/72 feet squared.

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Answer:

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Step-by-step explanation:

Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.

Initial velocity u with which the ball is projected upwards = + 120 ft/s

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Using the formula:

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0² - 120² = 2 × (- 32) h

=> h = 120²/2 × 32 = 225 feet

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