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3 years ago

Frank and Latoya each ran every day as part of an exercise routine. Frank ran

1 answer:

5 0

3 miles each day for x days is 3x
5 miles each day for y days is 5y
Frank ran at least as many miles as Latoya is 3x >/= 5y

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James wants to compete in the international speed texting competition next year where participants compete on text speed and acc

mario62 [17]

Answer:

A.2.5 B.3. C.3.5 D. 2+.5m=Cps(character per second)

Step-by-step explanation:

6 0

3 years ago

I REALLY NEED HELP ON 40 and 41, 50 POINTS

photoshop1234 [79]

Question 40 is D because from looking at the graph, its is symmetrical and the mean is the average, which usually the middle of the graph, so is the median. The median and mean would be within the 2.1-3 category because its the middle of the graph.

Question 41 is B because every pound is 16 ounces. If you multiply 16 and 12.5, you'll get 200.

3 0

3 years ago

Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel

GarryVolchara [31]

Answer:

The unusual $X$ values for this model are: $X = 0, 1, 2, 7, 8$

Step-by-step explanation:

A binomial random variable $X$ represents the number of successes obtained in a repetition of $n$ Bernoulli-type trials with probability of success $p$ . In this particular case, $n = 8$ , and $p = 0.53$ , therefore, the model is ${8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}$ . So, you have:

$P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024$

$P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215$

$P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848$

$P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912$

$P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695$

$P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431$

$P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371$

$P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442$

$P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062$

The unusual $X$ values for this model are: $X = 0, 1, 7, 8$

6 0

3 years ago

Read 2 more answers

The Kuroshio Sea tank is 27m long, 35m wide and 10m deep. What is the volume of the tank? Show your

umka21 [38]

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

Step-by-step explanation:

The given is,

Kuroshio Sea tank is 27m long, 35m wide and 10m deep.

Step:1

Sea tank looks like a rectangular prism,

Formula to calculate the volume of rectangular prism,

$Volume, V =whl$ .............................(1)

Where, w - Width of the rectangular prism

h - Height or depth of the rectangular prism

l - Length of the rectangular prism

From given,

w = 35 meters

l = 27 meters

h = 10 meters

Equation (1) becomes,

$V = (35)(10)(27)$

$= (945)(10)$

$=9450$

Volume of the sea tank, V = 9450 Cubic meters

Result:

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

3 0

3 years ago

HEYYYY GUYYYSSS HELPP MEEE, ILL MARK YOU BRAINIEST. PLEEEAAASEEEE thankkyouu

VikaD [51]

Answer:

Step-by-step explanation:

A dependent variable in an expression is one whose value can be determined only when the value of other variable (i.e independent) is known.

A. The cost at the fitness center depends on the number of months (x).

The cost is the dependent variable, and number of months (x) is the independent variable.

f(x) = 100 + 40x

Example, the cost paid for 12 months can be determined as;

f(12) = 100 + 40(12)

= 100 + 480

= 580

Thus, $580 would be paid for 12 months at the fitness center.

B. The lettuce is sold at $1.69 per pound. The cost depends on the number of pounds of lettuce bought.

The cost is the dependent variable, while the number of pounds of lettuce (x) bought is the independent variable.

So that;

f(x) = 1.69x

The cost of 10 pounds of lettuce can be determined as;

f(x) = 1.69(10)

= 16.9

Thus, the cost of 10 lb of lettuce is $16.90.

6 0

2 years ago