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Ivahew [28]
3 years ago
7

Why my answer is incorrect?Explain plezz

Mathematics
1 answer:
Alona [7]3 years ago
8 0

Because you put stickers all over it
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What is -a^-2 if a=-5
Leviafan [203]
-a^{-2}=-(-5)^{-2}=-\left(\dfrac{1}{-5}\right)^2=-\dfrac{1}{25}
3 0
3 years ago
At any point in time, there could be bicycles, tricycles, and
Aleksandr-060686 [28]

Answer:

There may be 1 or 3 tricycles in the parking lot.

Step-by-step explanation:

Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:

13 x 4 + 1 x 3 + 1 x 2 = 57

11 x 4 + 1 x 3 + 3 x 2 = 53

10 x 4 + 3 x 3 + 2 x 2 = 53

8 x 4 + 5 x 3 + 2 x 2 = 51

10 x 2 + 1 x 3 + 4 x 4 = 39

9 x 3 + 1 x 2 + 5 x 4 = 49

Therefore, there may be 1 or 3 tricycles in the parking lot.

6 0
3 years ago
Use identities to find the values of the sine and cosine functions for the following angle measure.
puteri [66]

Using the cosine double angle formula,

\cos 2\theta=2\cos^2 \theta-1=\frac{12}{13}\\\\2\cos^{2} \theta=\frac{25}{13}\\\\\cos^{2} \theta=\frac{25}{26}\\\\\boxed{\cos \theta=\frac{5}{\sqrt{26}}}

(Note I took the positive case since \theta terminates in the first quadrant)

Using the Pythagorean identity,

\sin^2 \theta+\cos^2 \theta=1\\\\\sin^2 \theta+\frac{25}{26}=1\\\\sin^2 \theta=\frac{1}{26}\\\\\boxed{\sin \theta=\frac{1}{\sqrt{26}}}

(Note I took the positive case since \theta terminates in the first quadrant)

6 0
1 year ago
What is 6/4 simplified
Rashid [163]
Since this is an improper fraction, you simplify it into a mixed number. 
4 goes into 6 1 time. 2 left left over, resulting in 1 2/4. Simplify that into 
1 1/2
6 0
3 years ago
Read 2 more answers
Factor the expression below.4x2 - 1
marusya05 [52]

Answer:

C. (2x – 1)(2x + 1)

Step-by-step explanation:

4x² – 1 = (2x)(2x) – 1 = (2x – 1)(2x + 1)

5 0
3 years ago
Read 2 more answers
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