What is 200/30 in a mixed number

2×y to the power2 -6×y to the power 2

sertanlavr [38]

2y to the second power= 4y
-6y to the second power= -36y

4 0

4 years ago

Challenge A movie theater sends out a coupon for 35% off the price of a ticket. Write an equation

Greeley [361]

Answer:

The equation is y= 0,65 x

If x is the price of the ticket without the coupon, and the theater offers a discount if you have a coupon, then having a coupon means that the price a person ultimately pays (y) is the original price (x) minus a 35% of this price: y= x -0.35 x . By association: y= (1-0.35) x and then y= 0.65 x.

The line should be in the first quadrant because the first quadrant allows you to represent a situation in which the dependent variable (y) and the independent variable (x) are both positive. This is the case in this exercise, because both prices, the one without discount (x) and the one with discount (y) are necessary positive (you can not pay a negative price!).

Step-by-step explanation:

The price without discount (or without the coupon) is x.

The price with discount (or with coupon) is y.
y and x are both related: y is a percentage of x, specifically, y is 35% smaller than x. This means that y =0.65 x.

3 0

3 years ago

Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo

kolezko [41]

Let x and y be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2x + y = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

x + 3y = 0.25

Solve for x and y. We have

y = 0.25 - 2x ==> x + 3 (0.25 - 2x) = 0.25

==> x + 0.75 - 6x = 0.25

==> 5x = 0.5

==> x = 0.1

==> y = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4x + 4y = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time t to fill one pool, we have

(3/5 pool/hour) (t hours) = 1 pool

==> t = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0

3 years ago

A satellite is composed of 30 modular units, each of which is equipped with a set of sensors, some of which have been upgraded.

Anit [1.1K]

Answer:

$\frac{1}{7}$

Step-by-step explanation:

The satellite has 30 modular units.

There are equal numbers of non-upgraded sensors in each unit.

Let us assume that on the entire satellite there are x numbers of upgraded sensors.

Then as per the given condition, there are $\frac{x}{5}$ number of non-upgraded sensors in one unit.

Therefore, the number of non-upgraded sensors on the entire satellite is $\frac{30x}{5}$ =6x

Hence, total number of sensors in the satellite is (x+ 6x) =7x

Therefore, the required fraction of the upgraded sensors is $\frac{x}{7x} =\frac{1}{7}$ . (Answer)

3 0

3 years ago

"Out of" is used when you want too divide . True or false ?

Alik [6]

Answer:

I think it's true

Step-by-step explanation:

7 0

3 years ago

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