Ask question

Ask question

All categories

4 years ago

13

What is 200/30 in a mixed number

1 answer:

mixer [17]4 years ago

7 0

6 20/30

hope it helps

You might be interested in

Please help me my grade is on the line

NemiM [27]

Answer shown and explanation above! Hope this helps!

5 0

3 years ago

3x+8x(-8x+3)= simplify it i guess

xxMikexx [17]

Answer:

27x-64x^2

Step-by-step explanation:

Distribute the 8x

3x-64x^2+24x

Combine like terms (3x and 24x)

27x-64x^2

6 0

3 years ago

Read 2 more answers

A local museum had a total of 38,627 vsitors last year. The museum was open everyday except for four holidays. On average how ma

sweet-ann [11.9K]

38,627/361 = 107.

107 people visit the museum every day according to the information given.

8 0

3 years ago

Read 2 more answers

What is the approximate value of q in the equation below?

gayaneshka [121]

<u>Given</u>:

The given equation is $q+\log _{2}(6)=2 q+2$

We need to determine the approximate value of q.

<u>Value of q:</u>

To determine the value of q, let us solve the equation for q.

Hence, Subtracting $\log _{2}(6)$ on both sides of the equation, we get;

$q=2 q+2-\log _{2}(6)$

Subtracting both sides of the equation by 2q, we have;

$-q=2-\log _{2}(6)$

Dividing both sides of the equation by -1, we have;

$q=\log _{2}(6)-2$

Now, substituting the value of $log_2(6)=2.585$ , we have;

$q=2.585-2$

Subtracting the values, we get;

$q=0.585$

Thus, the approximate value of q is 0.585

Hence, Option C is the correct answer.

5 0

4 years ago

Read 2 more answers

Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers

lidiya [134]

Answer:

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

Step-by-step explanation:

We are given $x=\sqrt{3}-1$ and we are asked to find the value of $x^2-x+1$ .

So we will need to find $x^2$ .

$x=\sqrt{3}-1$

Square both sides:

$x^2=(\sqrt{3}-1)^2$

Expand using identity: $(x-a)^2=x^2-2ax+a^2$ .

$x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2$

$x^2=3-2\sqrt{3}+1$

$x^2=4-2\sqrt{3}$

Let's go back to the full $x^2-x+1$ .

$x^2-x+1$

$(4-2\sqrt{3})-(\sqrt{3}-1)+1$

$4-2\sqrt{3}-\sqrt{3}+1+1$

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

5 0

4 years ago