The solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
<h3>How to determine the solution set of the equation?</h3>
The equation is given as:
x^2 + 2x - 48 = 0
A quadratic equation is represented as:
ax^2 + bx + c = 0
By comparing both equations, we have
a = 1, b = 2 and c = -48
The solution of the quadratic equation is then calculated using
x = (-b ± √(b^2 - 4ac))/2a
Substitute values for a, b and c in the above equation
x = (-2 ± √(2^2 - 4 * 1 * -48))/2 * 1
This gives
x = (-2 ± √196)/2
Evaluate the square root of 196
x = (-2 ± 14)/2
Divide through by 2
x = -1 ± 7
Hence, the solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
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Answer:
b = $48000, m = $3187.5 / year
Step-by-step explanation:
The equation of a linear function is given as y = mx + b, where m is the rate of change, b is the value of y when x = 0, y = dependent variable and x = dependent variable.
Given that V = mt + b:
b = initial price of the house at 0 years = $48000
V = mt + 48000, At 8 years the house is appraised at $73,500
73500 = 8m + 48000
8m = 73500 - 48000
8m = 25500
m = 3187.5
This is the possible answer and if my answer is wrong then the formula i used is absolutly right so you may proceed.
999 - 100 + 1 = 900
There are 900 numbers between 100 and 999 (inclusive)
We group the numbers into groups of 3s. So we find one number divisible by 3 in every group.
Number of numbers that can be divided by 3 = 900 ÷ 3 = 300
Number of numbers that can be divided by 3 = 300
We group the numbers into groups of 4s. So we find one number divisible by 4 in every group.
Number of numbers that can divided by 4 = 900 ÷ 4 = 225
Number of numbers that can divided by 4 = 225
Among the group of 4s, there is 1/3 that are already inclusive in divisible by 3.
225 ÷ 3 = 75
Number of numbers that can divided by 4 = 225 - 75 = 150
Total numbers of positive integers divisible by three and fours = 300 + 150 = 450
59° + 81°+ x° = 180°
140° + x° = 180°
x = 40°
