14 over 4509 would be an equvilent fraction
Answer: 241/4%
hope this helped
Answer:
The adult and the child ticket are both 8 dollars
Step-by-step explanation:
x =adult ticket price
y = child ticket price
I will assume you forget to put that they sold 2 child tickets on the second day
7x+5y=96 and 3x+2y= 40
I will use elimination. Multiply the first equation by 2 and the second equation by -5 to eliminate y
2(7x+5y)=96*2
14x + 10y = 192
The second equation
-5(3x+2y)= 40*-5
-15x -10y = -200
Add the equations together
14x + 10y = 192
-15x -10y = -200
------------------------
-x = -8
Multiply by -1
x = 8
Now we need to find y
3x+2y= 40
3(8) +2y = 40
24+2y = 40
Subtract 24 from each side
24-24 +2y = 40-24
2y = 16
Divide by 2
2y/2 =16/2
y =8
The adult and the child ticket are both 8 dollars
Answer:
48 or 47
Step-by-step explanation:
858/18 = 47.6
(x+2)^3=x^3+2^3+3*x^2*2+3x*2^2=x^3+8+6x^2+12x
The coeficient of the x^2 is 6.
